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Stolb23 [73]
3 years ago
5

The image is the problem: ty :P

Mathematics
1 answer:
vlada-n [284]3 years ago
7 0
Answer: the slope is 2/3
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PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST​
shusha [124]

Answer:

A. 49 + 16 (t - 1)

Step-by-step explanation:

Plug in t = 1 to test for the first hour:

49+16(1-1)=49+16(0)=49

Test as many values as you like, but testing t = 5:

49+16(5-1)=49+16(4)=49+64=113

You can see that plugging in just a few values confirms the answer.

8 0
2 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
PLEASE HELP If You Are not SURE please don't answer PLEASE show work and steps
Ivanshal [37]
63+12x<15
12x<-48 (subtract 63 from both sides)
x<-4 (divide out the 12)
8 0
3 years ago
Read 2 more answers
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GalinKa [24]
The answer is (D) ....
6 0
3 years ago
Read 2 more answers
Guidelines for the amount of supplementary nitrogen needed to grow winter wheat depend on the amount of nitrogen in the soil​ (a
Ierofanga [76]

The net profit or income for case A and case B based on the information will be $9250 and $9500 respectively.

<h3>How to compute the net profit?</h3>

Case A:

Based on the information, the price of fertilizer will be:

= 0.25 × 100 × 50

= $1250

Price of wheat = 3.50 × 50 × 50

= $10500

Net profit = $10500 - $1250

= $9250

Case B:

Price of fertilizer will be:

= 0.50 × 70 × 50

= $1750

Price of wheat = 4.50 × 50 × 50

= $11250

Net profit = $11250 - $1750

= $9500

Therefore, the net profit or income for case A and case B based on the information will be $9250 and $9500 respectively.

Learn more about net income on:

brainly.com/question/15530787

#SPJ1

3 0
1 year ago
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