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2 years ago

Please help no links please

Mathematics

1 answer:

allsm [11]2 years ago

8 0

Answer:

Step-by-step explanation:

The secant- tangent angle MLK is half the difference of the intercepted arcs, that is

$\frac{1}{2}$ (KN - KM) = 70° ( multiply both sides by 2 to clear the fraction )

KN - KM = 140°

KN - 61° = 140° ( add 61° to both sides )

KN = 201° → C

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What I need to do with this problems

alina1380 [7]

Answer:

L x W x H =Area

Step-by-step explanation:

8 0

3 years ago

So I have a question, this : Insert 2 grouping symbols to make the equation true

kotykmax [81]

Between 4 and 6 is where u put the grouping symbols!

3 0

3 years ago

I am confused please help

Otrada [13]

Answer:

3 tiles will not fit together.

Step-by-step explanation:

Measure of an Interior angle of a polygon = $\frac{(n-2)\times 180}{n}$

Here, n = number of sides of the polygon

Therefore, measure of the interior angles of a regular hexagon,

A = $\frac{(6-2)\times 180}{6}$

A = 120°

Similarly, interior angle of the regular pentagon,

B = $\frac{(5-2)\times 180}{5}$

B = 108°

Now m∠A + m∠B + m∠C = 360°

m∠C = 360° - (120° + 108°)

= 132°

To fit the given three tiles perfectly, interior angle (∠D) of the third Octagonal tile should be 132°.

D = $\frac{(8-2)\times 180}{8}$

D = 135°

m∠C ≠ m∠D

Therefore, 3 tiles will not fit together.

8 0

2 years ago

WILL MARK BRAINLIEST PLEASE HELP

IRINA_888 [86]

Answer:

(1,2)

Step-by-step explanation:

half it! :)

6 0

2 years ago

Read 2 more answers

Work out the formula of the nth term in the following quadratic sequence:<br> 19, 15, 9, 1...

Butoxors [25]

In a quadratic sequence we'll get a linear first difference and a constant second difference. Let's verify that.

n 1 2 3 4

f(n) 19 15 9 1

1st diff -4 -6 -8

2nd diff 2 2

We see that we got a constant second difference. We could just extend that and work back up to get more values.

n 1 2 3 4 5 6 7

f(n) 19 15 9 1 -9 -21 -35

1st diff -4 -6 -8 -10 -12 -14

2nd diff 2 2 2 2 2

That's just an aside; we're after the general formula. We have

f(1)=19, f(2)=15, f(3)=9

In general we can assume

f(n) = an² + bn + c

We get three equations in three unknowns,

19 = a(1²)+b(1)+c = a+b+c

15 = a(2²) + b(2) + c = 4a + 2b + c

9 = a(3²) + b(3) + c = 9a + 3b + c

That's a 3x3 linear system; it's easy to solve directly. Subtracting pairs,

4 = -3a - b

6 = -5a - b

Subtracting those,

-2 = 2a

a = -1

b = -3a -4 = -1

c = 19-a-b = 21

Answer: f(n) = -n² - n + 21

Check:

f(1) = -1 - 1 + 21 = 19, good

f(2) = -4 - 2 + 21 = 15, good

f(3) = -9 - 3 + 21 = 9, good

f(4) = -16 - 4 + 21 = 1, good

Let's check our extended table, how about

f(7)= -49 - 7 + 21 = -35, good

6 0

2 years ago