Answer:
P = 3.37 x 10 ⁶ Pa
Explanation:
Given that
A= 1.6 cm²
m = 55 kg
The weight W= m g
W= 55 x 9.81 ( g= 9.81 m/s²)
W= 539.55 N
We know that force per unit area is known as pressure( P)
P = W/A
By putting the values
P= 539.55/1.6 N/cm²
P=337.21 N/cm²
P=337.21 x 10⁴ N/m²
P = 3.37 x 10 ⁶ Pa
Answer:
Given:
q1=8*10-9C
q2=3*10-9C
q3=7*10-9C
S=3m
But electric potential V=kq/r
W=q x change in V
Va=k/r(q1+q2/✓2+q3)
Va=9*10^9/3(8*10^-9+3*10^-9/✓2+7*10^-9)=49.5V
VB=k/0.5r.✓2(q1+q2+q3)
Were r is distance at center given by
r=1/2(r)✓2
VB=9*10^9/0.5*3✓2(8*10^-9+3*10^-9+7*10^-9)=33.9v
Change in = Va-Vb=49.5-33.9=15.6V
Work=r*V=2*10^-9*15.6=3.12×10^-8J
Answer / Explanation:
To properly answer this question, let us define what a grain boundary is:
A grain boundary is the interface between multiple grains or crystals in a poly-crystalline material. They could also be refereed to as defects in the crystal structure and tend to decrease the electrical and thermal conductivity of structures.
Now, if we refer back to the question asked,
(a) The surface energy is grater than the grain boundary energy because surface atom have fewer bonds than atom along a grain boundary.
Consequentially, the lower the number of bonds formed, the higher the energy
(b) A higher angle grain boundary has higher misalignment and hence greater disruption of bonds (lesser number of bonds) than a small angle grain boundary. Therefore, a high angle grain boundary has higher energy.
When more than one force acts upon an object, the vector sum of these forces is the resultant force. When the resultant force on an object is zero, it will remain at rest if it is at rest, or continue to move in a straight line at a constant velocity if it is in motion. ... That is, there is zero acceleration.
To solve this problem we will start by applying the given load ratio, and we will rely on the two types of distances given. Later we will use Gauss's law and through its integrals, in which it is equivalent to the potential we will obtain its value in the center of the sphere. Since it is uniformly charged we have to,
By Gauss Law
Here, E is the electric Field and is equal to
For being the Permeability constant at free space
Replacing with the previous value we have,
Then the value of the electric field is,
Now potential