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Allushta [10]
4 years ago
8

which of the four terms below includes the other three terms (1)community (2)ecosystem (3)population (4)individuala

Physics
1 answer:
Brut [27]4 years ago
7 0
I think the answer is 3, population.
You might be interested in
Area =<br> 22 m<br> 18 m<br> 16 m
VikaD [51]

First divide the parts where it is a rectangle and semicircle.

Find the area of the rectangle:

A = length × breadth

A = 18m × 16m

A = 288m²

Then find the area of the semi-circle. We know that the area of a circle is πr² and half that area gives you the area of a semi-circle: πr²/2

A = πr²/2

A = π(6)²/2

A = 18πm² or 56.549m²

Total Area = <u>288m² + 18πm² </u>

                                OR

                    288m² + 56.549m² = <u>344.549m²</u>

<em>Hope it helps!</em>

7 0
2 years ago
If the height of the ramp was 1.2 m above the floor, how long would it take for the marble to hit the ground after it left the r
Evgesh-ka [11]
It would take at less 10 minte i guess this the right awnser

8 0
4 years ago
A sphere of radius 5.15 cm and uniform surface charge density +12.1 µC/m2 exerts an electrostatic force of magnitude 35.9 ✕ 10-3
rosijanka [135]
The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
A=4 \pi r^2 = 4 \pi (0.0515 m)^2 = 0.033 m^2

So the total charge on the surface of the sphere is, using the charge density 
\rho=+1.21  \mu C/m^2 = +1.21 \cdot 10^{-6} C/m^2:
Q= \rho A = (+1.21 \cdot 10^{-6} C/m^2)(0.033 m^2)=4.03 \cdot 10^{-8}C

The electrostatic force between the sphere and the point charge is:
F=k_e  \frac{Qq}{r^2}
where
ke is the Coulomb's constant
Q is the charge on the sphere
q=+1.75 \muC = +1.75 \cdot 10^{-6}C is the point charge
r is their separation

Re-arranging the equation, we can find the separation between the sphere and the point charge:
r=\sqrt{ \frac{k_e Q q}{F} }= \sqrt{ \frac{(8.99 \cdot 10^9 Nm^2 C^{-2})(4.03 \cdot 10^{-8} C)(1.75 \cdot 10^{-6}C)}{35.9 \cdot 10^{-3}N} }=0.133 m=13.3 cm
8 0
3 years ago
Find the range of projectile launched at the angle of 45 with an intial velocity of 25 m/s
Mekhanik [1.2K]

Answer:

10

Explanation:

Given that :

Initial Velocity (u) = 25 m/s

Range can be obtained using the relation :

Range = (u² * sin2θ) / g

g = 10m/s ; θ = 45

Range = [10² * sin2(45)] / 10

Range = [100 * 1] ÷ 10

Range = 10

5 0
3 years ago
Assume that two cars have the same kinetic energy, but that the red car has twice the speed of the blue car. We then know that t
Anna71 [15]

Answer:

equal

Explanation:

8 0
3 years ago
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