Answer:
A 200mm lever and a 240 mm diameter pulley are welded to the axle BE that is supported by bearings at C and D. If a 860N vertical load is applied at A when the lever is horizontal, determine (a)the tension in the cord, (b)the reactions at C and D. assume that the bearing at D does not exert axial thrust.
see explanation
Explanation:
Part a
The tension in the cord
860(200) - T(120) = 0
T(120) = 172000
T =1433.33N
The tension in the cord (T) = 1433.33N
Part b
Apply the moment law of equilibrium at point D about y-axis.
sustitute 1433.33N for T
The reaction at C along x-axis 477.78N
Apply the moment law of equilibrium at point D about x-axis
The reaction at C along y-axis is 143.33N
Apply the force law of equilibrium along z direction.
The reaction at C along z-axis is 0N
Apply the force law of equilibrium along x direction.
substitute 477.78N for 
and 143.33N for 
The reaction at D along x-axis is -1911.11 N
Apply the force law of equilibrium along y direction.
substitute 1433.33 for 
Answer:
Explanation:
Solubility is affected by current concentration, mechanical disturbance, temperature and pressure. So the answers are:
- Increasing temperature decreases the solubility of gases.
- Stirring increases the solubility of solids.
- Increasing pressure increases the solubility of gases.
- Decreasing the amount of solvent decreases the solubility of solids, liquids, and gases.
Answer:
Image result for what is the force the when does when Gravity pushes you
The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.
Explanation:
Image result for what is the force the when does when Gravity pushes you
The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.
Answer:
Explanation:
mass of the fellow ( m ) = 66kg
acceleration of fellow a
v = u + at
4.5 = 0 + a x 2
a = 4.5 /2
= 2.25 m / s²
Net force acting on fellow in upward direction by the surface of elevator
R - mg where R is reaction force of the surface of the elevator
Applying Newton's law of motion
R - mg = ma
R = m (g +a )
= 66 x ( 9.8 + 2 )
= 778.8 N
This will be the scale reading .
