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grigory [225]
3 years ago
11

Literal equation Solve for W.

Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0
Hey it’s a thank me later :)
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Solve the system of linear equations by substitution x=5y+2 and x-4y=5
never [62]

Answer:

(17,3)

Step-by-step explanation:

Equation 1.

x=5y+2

Equation 2.

x-4y=5

To solve with substitution, it looks like the x-variable in the first equation is already isolated. So, plug the first equation into the x-variable in the second equation.

x-4y=5

(5y+2)-4y=5

y+2=5

y=3

Now that we found y, plug y into one of the equations to solve for x.

x=5y+2

x=5(3)+2

x=15+2

x=17

(17,3)

6 0
2 years ago
So me and Patrick have the same IQ
JulsSmile [24]

Answer:

25 seconds

Step-by-step explanation:

The radius of a hailstorm varies directly

with the amount of time that it was in a cloud.

Radius = k x Time (in the cloud)

k is the constant of proportionality

R = k x T

0.5 = k x 10

k = 0.5/10

k = 0.05

Formula: R = 0.05 x T

1.25 = 0.05 x T

Time = 1.25/0.05

Time = 25 seconds.

Hope this helps :) !

8 0
2 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
If lin runs 24 laps at the same rate how long does it take her
sveta [45]

Answer:

is that all

Step-by-step explanation:

if she runs 24 laps a minute then the next minute she would of ran 48

5 0
2 years ago
Read 2 more answers
Alexia designed a logo 2 inches wide and 1.5 inches tall to be used on her school's notebooks. The school wants the logo on the
Xelga [282]

If the original logo is 2 inches wide and the logo has to be 8 inches wide, then the new logo will be 4 times larger. Therefore, we have to multiply 1.5 by 4 to get our new height.

1.5 x 4 = 6 inches tall.

Hope this helped!

5 0
2 years ago
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