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Answer:
2.675 moles of Chlorine gas are required
Explanation:
Chlorine gas, Cl2, reacts with NaBr to produce NaCl and Br2 as follows:
Cl2 + 2NaBr → 2NaCl + Br2
<em>Where 1 mole of chlorine gas produce 2 moles of NaCl</em>
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Thus, to produce 5.35 moles of NaCl are required:
5.35mol NaCl * (1mol Cl2 / 2mol NaCl) =
<h3>2.675 moles of Chlorine gas are required</h3>
A chemical symbol represent the number of an element
Answer:
1.69 moles of ammonia are needed to produced 45.5 g of water.
Explanation:
Given data:
Mass of water = 45.5 g
Moles of ammonia required = ?
Solution:
Chemical equation:
4NH₃ + 5O₂ → 4NO + 6H₂O
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 45.5 g/ 18 g/mol
Number of moles = 2.53 mol
Now we will compare the moles of water with ammonia.
H₂O : NH₃
6 : 4
2.53 : 4/6×2.53 = 1.69 mol
1.69 moles of ammonia are needed to produced 45.5 g of water.
