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vodka [1.7K]
3 years ago
9

The molecule below contains both an aldehyde and a ketone functional group. select only the carbonyl carbon atom of the aldehyde

functional group. identify the carbon atom by selecting the atom and assigning it a map number of 1. to do this, right-click on an atom and choose atom properties.

Chemistry
1 answer:
4vir4ik [10]3 years ago
7 0
Carbonyl compounds are those compounds in which carbon aton is doubly bonded to oxygen atom.
The hybridization of carbon and oxygen in carbonyl compounds is Sp². Folowing are examples of carbonyl compounds,
                                             
                                               1. Ketones
                                               2. Aldehydes
                                               3. Carboxylic Acids
                                               4. Acyl Halides
                                               5. Amides
                                               6. Esters
                                               7. Anhydrides e.t.c
Result:
          In given the structure the carbonyl groups are highlighted RED, as shown below.

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Write the net ionic equation for the reaction that occurs when equal volumes of 0.546 M aqueous acetylsalicylic acid (aspirin) a
Tatiana [17]

Answer:

C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to figure out the required net ionic equation by firstly writing out the complete molecular equation between aspirin and sodium acetate:

C_9H_8O_4+NaC_2H_3O_2\rightarrow C_2H_4O_2+NaC_9H_7O_4

Whereas acetic acid and sodium acetylsalicylate are formed. Now, we write the complete ionic equation whereby sodium acetate and sodium acetylsalicylate are ionized because they are salts yet neither aspirin nor acetic acid are ionized as they are weak acids:

C_9H_8O_4+Na^++C_2H_3O_2^-\rightarrow C_2H_4O_2+Na^++C_9H_7O_4^-

Finally, for the net ionic equation we cancel out the sodium spectator ions to obtain:

C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-

Regards!

7 0
3 years ago
Срочноооооооооооооо!!!!
Ymorist [56]

Answer:

I can't answer this as I am not able to read the Question

4 0
3 years ago
Which metals may be oxidized by H+ under standard-state conditions? Ag+(aq) + e– → Ag(s) E° = 0.80 V Cu2+(aq) + 2e– → Cu(s) E° =
Debora [2.8K]
Answer is: tin and zinc, because they standard potential as less than zero.
Tin and zinc are oxidized to tin and zinc cations (with +2 charge) and hydrogen anions are reduced to hydrogen molecules with neutral charge.
Zn → Zn²⁺ + 2e⁻; 2H⁺ + 2e⁻ → H₂.
<span>Oxidation is increase of oxidation number  and reduction is decrease of oxidation number.</span>
8 0
3 years ago
An ionic compound has a slightly negative heat of solution in water. would you expect it to be soluble or insoluble in water?
Grace [21]
The ionic compound will be soluble in water. 
The value of the heat of solution of a substance is one of the factors that determine whether a substance will dissolve or not. A negative heat of solution signifies that the reaction will be spontaneous, so the ionic compound will dissolve in water.
3 0
3 years ago
The table shows the amount of radioactive element remaining in a sample over a period of time.
Lunna [17]

Answer:

1. The half-life is 22 years.

2. 132 years

Explanation:

1. Determination of the the half-life.

The half-life of an element is the time taken for half the element to decay.

From the table given above, the original amount of the element 45 g. If we divide 45 by 2, we'll have 22.5 g as half the original amount of element.

Now, the time taken to obtain 22.5 g as shown from the table is 22 years.

Thus, the half-life the element is 22 years.

2. Determination of the time.

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Time (t) =?

Next, we shall the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

4.8125 = 1/2ⁿ × 308

Cross multiply

4.8125 × 2ⁿ = 308

Divide both side by 4.8125

2ⁿ = 308 / 4.8125

2ⁿ = 64

Express 64 in index form with 2 as the base.

2ⁿ = 2⁶

n = 6

Thus, 6 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Number of half-lives (n) = 6

Half-life (t½) = 22 years

Time (t) =?

n = t / t½

6= t / 22 years

Cross multiply

t = 6 ×22

t = 132 years.

Thus, the time taken is 132 years.

6 0
3 years ago
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