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vodka [1.7K]
3 years ago
9

The molecule below contains both an aldehyde and a ketone functional group. select only the carbonyl carbon atom of the aldehyde

functional group. identify the carbon atom by selecting the atom and assigning it a map number of 1. to do this, right-click on an atom and choose atom properties.

Chemistry
1 answer:
4vir4ik [10]3 years ago
7 0
Carbonyl compounds are those compounds in which carbon aton is doubly bonded to oxygen atom.
The hybridization of carbon and oxygen in carbonyl compounds is Sp². Folowing are examples of carbonyl compounds,
                                             
                                               1. Ketones
                                               2. Aldehydes
                                               3. Carboxylic Acids
                                               4. Acyl Halides
                                               5. Amides
                                               6. Esters
                                               7. Anhydrides e.t.c
Result:
          In given the structure the carbonyl groups are highlighted RED, as shown below.

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What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

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Given mass= 19.2 g/mole

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Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

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