The molecule below contains both an aldehyde and a ketone functional group. select only the carbonyl carbon atom of the aldehyde
functional group. identify the carbon atom by selecting the atom and assigning it a map number of 1. to do this, right-click on an atom and choose atom properties.
1 answer:
Carbonyl compounds are those compounds in which carbon aton is doubly bonded to oxygen atom.
The hybridization of carbon and oxygen in carbonyl compounds is Sp². Folowing are examples of carbonyl compounds,
1. Ketones
2. Aldehydes
3. Carboxylic Acids
4. Acyl Halides
5. Amides
6. Esters
7. Anhydrides e.t.c
Result:
In given the structure the carbonyl groups are highlighted RED, as shown below.
The hybridization of carbon and oxygen in carbonyl compounds is Sp². Folowing are examples of carbonyl compounds,
1. Ketones
2. Aldehydes
3. Carboxylic Acids
4. Acyl Halides
5. Amides
6. Esters
7. Anhydrides e.t.c
Result:
In given the structure the carbonyl groups are highlighted RED, as shown below.
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The mass decay rate is of the form
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.
Because the half-life is 30 years, therefore
After 60 years, the mass remaining is
Answer: 750 g
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.
Because the half-life is 30 years, therefore
After 60 years, the mass remaining is
Answer: 750 g
Acid palmitic acid has higher melting point, because it has two more methylene groups.
Acid palmitic acid has higher melting point, because it has two more methylene groups.
Giving it a greater surface area and therefore more intermolecular van der waals interact than the myristic acid.
stearic arid
linoleic acid (two double bond)
Stearic acid has higher Melting point, because it does not have any Carbon-Carbon double bonds, whereas linoleic acid has two cis double bonds which prevent the molecules from packing closely together.
Oleic Acid and Linoleic acid.
-one double bond (cis)
Acid palmitic acid has higher melting point, because it has two more methylene groups.
For more such question on methylene group.
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