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horsena [70]
4 years ago
5

Please answer :( They are fractions and I suck at them.

Mathematics
2 answers:
Ann [662]4 years ago
7 0

Answer:

8/15 (fraction) or 0.5333333333333...

Step-by-step explanation:

neonofarm [45]4 years ago
7 0

Answer:

4/15

Step-by-step explanation:

115×41=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

1×415×1=415

This fraction cannot be reduced.

Therefore:

115×41=415

Apply the fractions formula for multiplication, to

115×41

and solve

1×415×1

=415

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expeople1 [14]

Answer:

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8 0
4 years ago
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If there are 624 calories in 3 servings, how many calories are in 1 serving
Zepler [3.9K]

Answer:

208 calories

Step-by-step explanation:

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7 0
3 years ago
Solve the inequality 7y-35<2(x-5)
AfilCa [17]

Answer:

x < 5

<u>Explanation:</u>

 7*x-35-(2*(x-5))<0

 (7x - 35) -  2 • (x - 5)  < 0

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Add  5  to both sides

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5 0
2 years ago
I just need #31 and #33 answered please.
sergiy2304 [10]

<h2><em><u>3</u></em><em><u>1</u></em><em><u>.</u></em><em><u>f</u></em><em><u>(</u></em><em><u>x</u></em><em><u>)</u></em><em><u> </u></em><em><u>=</u></em><em><u>{</u></em><em><u>3</u></em><em><u>—</u></em><em><u>x</u></em><em><u>,</u></em><em><u> </u></em><em><u> </u></em><em><u>x≤1</u></em></h2><h2><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u>{</u></em><em><u>2</u></em><em><u>x</u></em><em><u>,</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>1</u></em><em><u><</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em></h2><h2><em><u>=</u></em><em><u> </u></em><em><u> </u></em><em><u>3</u></em><em><u>+</u></em><em><u>1</u></em><em><u>+</u></em><em><u>2</u></em><em><u>+</u></em><em><u>1</u></em><em><u>=</u></em><em><u>7</u></em></h2><h2><em><u>=</u></em><em><u> </u></em><em><u> </u></em><em><u>x</u></em><em><u>+</u></em><em><u>x</u></em><em><u>+</u></em><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u>3</u></em><em><u>x</u></em><em><u> </u></em></h2><h2><em><u>=</u></em><em><u> </u></em><em><u> </u></em><em><u>3</u></em><em><u>x</u></em><em><u>+</u></em><em><u>7</u></em><em><u>=</u></em><em><u>1</u></em><em><u>0</u></em><em><u>x</u></em></h2><h2><em><u>=</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>×</u></em><em><u>=</u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em></h2><h2><em><u>=</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>—</u></em><em><u>—</u></em><em><u>—</u></em></h2><h2><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u>1</u></em><em><u>0</u></em></h2><h2><em><u>=</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>3</u></em></h2><h2><em><u>n</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>,</u></em></h2><h2><em><u>3</u></em><em><u>—</u></em><em><u>x</u></em><em><u>=</u></em><em><u>3</u></em></h2><h2><em><u>x≤1</u></em><em><u>=</u></em><em><u>3</u></em><em><u>×</u></em><em><u>1</u></em><em><u>=</u></em><em><u>3</u></em></h2><h2><em><u>2</u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>×</u></em><em><u>3</u></em><em><u>×</u></em><em><u>1</u></em><em><u>×</u></em><em><u>3</u></em><em><u>=</u></em><em><u>9</u></em></h2><h2><em><u>1</u></em><em><u><</u></em><em><u>x</u></em><em><u>=</u></em><em><u>9</u></em><em><u>×</u></em><em><u>3</u></em><em><u>=</u></em><em><u>2</u></em><em><u>7</u></em><em><u>,</u></em><em><u>,</u></em><em><u>,</u></em><em><u>,</u></em><em><u>,</u></em><em><u>,</u></em><em><u>,</u></em><em><u>,</u></em><em><u> </u></em></h2><h2><em><u>how</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>done</u></em><em><u> </u></em><em><u>do</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>all</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em></h2><h2><em><u>note</u></em><em><u>:</u></em><em><u>please</u></em><em><u> </u></em><em><u>understand</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>write</u></em><em><u> </u></em></h2><h2 />
5 0
4 years ago
Some one help me on this one
aleksandrvk [35]
The answer is III only, or D. 


We can start to solve this by knowing what the HL theorem means. The HL theorem, like its name implies, shows says that if a hypotenuse and leg of a triangle are congruent to the hypotenuse and leg of a different triangle, then the triangles are congruent. The only triangle that we see a hypotenuse congruent in is in figure III. In figure II, those congruent sides are both legs while in figure I we just see 2 congruent angles. Now in figure III, we can also see that two legs are congruent because of the reflexive property. That means that the answer is III, or D. 
5 0
3 years ago
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