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fredd [130]
3 years ago
9

A student creates an electromagnetic wave and then reverses the direction of the current. Which of the following will happen to

the magnetic field?
Physics
1 answer:
mash [69]3 years ago
7 0

Answer:

I believe the electromagnetic field should be reversed.

Explanation:

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Points P and Q are located at (0, 2, 4) and (-3, 1,5). Calculate
Akimi4 [234]

Answer:

a) The position vector of P is \vec P =(0, 2,4).

b) The distance vector from P to Q is \overrightarrow{PQ} = (-3,-1,1).

c) The distance between P and Q is \|\overrightarrow{PQ}\|=\sqrt{11}.

d) A vector parallel to PQ with magnitude of 10 is \vec v = \left(-\frac{30\sqrt{11}}{11},-\frac{10\sqrt{11}}{11}, \frac{10\sqrt{11}}{11} \right).

Explanation:

a) The position vector of a point is the vector displacement from the origin to the location of the point. That is:

\vec P = (0,2,4)-(0,0,0)

\vec P = (0-0, 2-0, 4-0)

\vec P =(0, 2,4)

The position vector of P is \vec P =(0, 2,4).

b) First, we calculate the position vector of point Q:

\vec Q = (-3,1,5)-(0,0,0)

\vec Q = (-3-0,1-0,5-0)

\vec Q =(-3,1,5)

The distance vector from P to Q is define by the following vectorial expression:

\overrightarrow{PQ} = \vec Q - \vec P (1)

\overrightarrow{PQ} = (-3,1,5)-(0,2,4)

\overrightarrow{PQ} =(-3-0,1-2,5-4)

\overrightarrow{PQ} = (-3,-1,1)

The distance vector from P to Q is \overrightarrow{PQ} = (-3,-1,1).

c) There are two approaches to calculate the distance between P and Q:

First Method - Pythagorean Theorem:

\|\overrightarrow{PQ}\| = \sqrt{(-3)^{2}+(-1)^{2}+1^{2}}

\|\overrightarrow{PQ}\|=\sqrt{11}

Second Method - Dot Product:

\|\overrightarrow{PQ}\| = \sqrt{\overrightarrow{PQ}\,\bullet\,\overrightarrow{PQ}} (2)

\|\overrightarrow{PQ}\| = \sqrt{(-3,-1,1)\,\bullet (-3,-1,1)}

\|\overrightarrow{PQ}\|=\sqrt{11}

The distance between P and Q is \|\overrightarrow{PQ}\|=\sqrt{11}.

d) To determine a vector parallel to PQ with a given magnitude is determined by the following expression:

\vec v = \frac{k}{\|\overrightarrow{PQ}\|} \cdot \overrightarrow{PQ} (3)

Where k is the scale factor.

If we know that \overrightarrow{PQ} = (-3,-1,1), \|\overrightarrow{PQ}\|=\sqrt{11} and k = 10, then the vector is:

\vec v = \frac{10}{\sqrt{11}}\cdot (-3,-1,1)

\vec v = \left(-\frac{30}{\sqrt{11}},-\frac{10}{\sqrt{11}},\frac{10}{\sqrt{11}}\right)

\vec v = \left(-\frac{30\sqrt{11}}{11},-\frac{10\sqrt{11}}{11}, \frac{10\sqrt{11}}{11} \right)

A vector parallel to PQ with magnitude of 10 is \vec v = \left(-\frac{30\sqrt{11}}{11},-\frac{10\sqrt{11}}{11}, \frac{10\sqrt{11}}{11} \right).

8 0
3 years ago
4. A baseball is pitched with a speed of 35 m/s. If the baseball has a mass of 0.146 kg, what is its
Allisa [31]

Answer: 89 J

Explanation:

3 0
3 years ago
Two charge spears are 20 cm apart and extract an attractive force of 8x10^-9 N on each other. Which will be the force of attract
Talja [164]

Answer:

3.2 × 10⁻⁸ N.

Explanation:

By Coulomb's Law, the magnitude of the electromagnetic force between two point charges is inversely proportional to the square of their separation, r. In other words,

\displaystyle \frac{F_1}{F_2} = {\left(\frac{r_2}{r_1}\right)}^{2}.

  • Initial electromagnetic force F_1 = 8\times 10^{-9}\;\text{N};
  • Initial Separation r_1 = 20\;\text{cm};
  • Final Separation r_2 = 10\;\text{cm}.

Final electromagnetic force:

\displaystyle F_2 = F_1 \cdot \left(\frac{r_2}{r_1}\right)^{2} = 8\times 10^{-9}\times \left( \frac{20}{10}\right)^{2} = 3.2\times 10^{-8}\;\text{N}.

4 0
4 years ago
Suppose it turns out that one in 1 million stars has a planet that at some point in its history is home to an advanced civilizat
natita [175]

It has been proposed that the total number of civilizations that have arisen in our galaxy would be closest to 100,000.

<h3>What is a galaxy?</h3>

A galaxy is a group of stars (solar systems), gas, and dust in a specific position in the Universe.

The Milky Way is the galaxy where we live and it has been proposed that this galaxy is full of dead civilizations.

In conclusion, the total number of civilizations that have arisen in our galaxy would be closest to 100,000.

Learn more about galaxies here:

brainly.com/question/13956361

#SPJ1

7 0
2 years ago
5. What is the velocity of a Nolan Catholic football player if he runs 200.0 m in 24.0 s?
Degger [83]

Answer:

\boxed{ \bold{ \huge{ \boxed {\sf{8.33 \: m \:/s \: }}}}}

Explanation:

Distance travelled = 200 metre

Time taken = 24 second

Velocity = ?

<u>Finding </u><u>the</u><u> </u><u>velocity</u><u> </u>

\boxed{ \sf{velocity =  \frac{distance \: travelled \: }{time \: taken}}}

\dashrightarrow{ \sf{velocity =  \frac{200 \: m}{24 \: s} }}

\dashrightarrow{ \sf{velocity = 8.33 \: m/s}}

Hope I helped!

Best regards!

6 0
3 years ago
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