Answer:
∆p=(m2v)kg.m/s
Explanation:
∆p=mv where v=2v. hence ∆p=m2v
Answer:
28.79%
Explanation:
Given
Design Speed, V = 120km/h = 33.33m/s
Radius, R = 300m
Side Friction, Fs = 0.09
Gravitational Constant = 9.8m/s²
Using the following formula, we'll solve the required rate of superelevation.
e + Fs = V²/gR where e = rate
e = V²/gR - Fs
e = (33.33)²/(9.8 * 300) - 0.09
e = 0.287853367346938
e = 28.79%
Hence, the required rate of superelevation for the curve is calculated as 28.79%
Answer:
1.35×10⁻⁷ m
37.278 mi/My
Explanation:
Speed of the tectonic plate= 6 cm/yr
Converting to seconds
So in one second it will move
In 71 seconds
The tectonic plate will move 1.35×10⁻⁵ cm or 1.35×10⁻⁷ m
Convert to mi/My
1 cm = 6.213×10⁻⁶ mi
1 M = 10⁶ years
Speed of the tectonic plate is 37.278 mi/My
Answer:
We live in a very adaptable environment. If we cannot adapt to the environment, we will not be able to survive.
Explanation:
Answer:
Explanation:
The torque of a force is given by:
where
F is the magnitude of the force
d is the distance between the point of application of the force and the centre of rotation of the system
is the angle between the direction of the force and d
In this problem, we have:
, the force
, the distance of application of the force from the centre (0,0)
, the angle between the direction of the force and a
Therefore, the torque is