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Mashcka [7]
3 years ago
11

What is the missing lengt? area = 405 m

Mathematics
2 answers:
VashaNatasha [74]3 years ago
6 0

Answer:

where's the graph?

Step-by-step explanation:

  1. This question can't be answered unless at least one length is already shown. Think about it, fool.
  2. Joeo Mama
LUCKY_DIMON [66]3 years ago
4 0

Answer:

20.1

Step-by-step explanation:

idunno, it's probably a square so i just rooted it.

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What is the common difference is this sequence: 5,17,29,41,53?
Zina [86]

Answer:

12

Step-by-step explanation:

To find the common difference, we take the 2nd term and subtract the first term

17-5 =12

We check it with the 3rd term minus the second term

29-17 = 12

The common difference is 12

We add 12 each time

5 0
4 years ago
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Vedmedyk [2.9K]
Huh come again? I’m not sure what you just said
6 0
3 years ago
On any given day, the probability that a large local river is polluted by carbon tetrachloride is 0.12. Each day, a test is cond
babymother [125]

Answer:

a) 0.2416

b) 0.4172

c) 0.0253

Step-by-step explanation:

Since the result of the test should be independent of the time , then the that the test number of times that test proves correct is independent of the days the river is correct .

denoting event a A=the test proves correct and B=the river is polluted

a) the test indicates pollution when

- the river is polluted and the test is correct

- the river is not polluted and the test fails

then

P(test indicates pollution)= P(A)*P(B)+ (1-P(A))*(1-P(B)) = 0.12*0.84+0.88*0.16 = 0.2416

b) according to Bayes

P(A∩B)= P(A/B)*P(B) → P(A/B)=P(A∩B)/P(B)

then

P(pollution exists/test indicates pollution)=P(A∩B)/P(B) = 0.84*0.12 / 0.2416 = 0.4172

c) since

P(test indicates no pollution)= P(A)*(1-P(B))+ (1-P(A))*P(B) = 0.84*0.88+  0.16*0.12 = 0.7584

the rate of false positives is

P(river is polluted/test indicates no pollution) = 0.12*0.16 / 0.7584 = 0.0253

4 0
3 years ago
Is the amount of rain in city upper b during april a discrete random​ variable, a continuous random​ variable, or not a random​
larisa [96]
Answer: It is a continuous random variable.

The amount of rain is a continuous random variable because it can take on all of the numbers on a number line.

For example, the actual amount of rain in April could be 1 inch. Or 1.4 inches. Or 1.45 inches. Or 1.452020980234 inches. There are an infinite possibilities for the amount of rainfall.
6 0
3 years ago
The total number of markers that Nancy has if she gives away 2/5 of her m markers to Amy
Archy [21]

Answer:

she has 3/5 left


7 0
4 years ago
Read 2 more answers
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