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Sergeeva-Olga [200]
2 years ago
8

The radius of a circle is 18 miles. What is the circle's area? Use 3.14 for (pi sign)

Mathematics
1 answer:
Lyrx [107]2 years ago
5 0
Don’t click on the link, it is a virus.... the answer is 18 squared x 3.14

So then you get 324x3.14, and you get 1,017.36

That is ur answer
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F Can anyone explain how too find the inverse of the function of this problem? f(x)= (x + 2)3.
Firlakuza [10]
The inverse function is f^-1 (x)= -2+(x/3) dont add the parenethese though, i used the parenethese to show that its x over 3. hope that helped! :D 
5 0
2 years ago
In the circle below, DB = 22 cm, and m<DBC = 60°. Find BC. Ignore my handwriting.​
Karo-lina-s [1.5K]

Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

m\angle DBC=\frac{1}{2}[arc\ DC]

substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

substitute the values

BC=(22)sin(30\°)=11\ cm

6 0
3 years ago
Can you guys help me on question 8 and 9 :)
Reika [66]

Answer:

for 8 i think its a b and c sorry if am wrong

8 0
2 years ago
A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32
zavuch27 [327]

Hypotenuse =39cm of right angle triangle! .

<u>Step-by-step explanation:</u>

Here we have , A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32  centimeters, and the length of the other leg is 25 centimeters. The student incorrectly says that the  length of the hypotenuse is 7.5 centimeters. We need to find:

A)

We have , One length as 32 cm and other as 25 cm , as

Perpendicular = 32cm\\Base=25cm

By Pythagoras Theorem ,

⇒ Hypotenuse^2 = Perpendicular^2+Base^2

⇒ Hypotenuse^2 =32^2+22^2

⇒ \sqrt{Hypotenuse^2} =\sqrt{1024+484}

⇒ Hypotenuse =39cm

So , Hypotenuse =39cm of right angle triangle! .

4 0
3 years ago
Read 2 more answers
Can someone help me with this page please I have an exam tomorrow, I need to remember the answers unfortunately :)
zimovet [89]

Answer:

1. B. ∠2 and ∠6

2. 50°

3. Option 1, Option 5, and Option 6.

4. 133°

<u>Work for question 4:</u>

180°-47° = 133°

Step-by-step explanation:

1.

Alternate means the angles are on different sides of the transversal (horizontal line in this case). Interior means they are between the parallel lines (lines a and b in this case). (∠2 and ∠6) and (∠3 and ∠7) are the alternate interior angles but only the first is an option.

2.

∠10 = ∠8+∠7 (corresponding angles so they are congruent)

∠10 is 140° and ∠8 is a right angle

140-90 = 50

∠7 = 50°

∠4 = 50° (∠7 and ∠4 are vertical angles so they are congruent)

3.

Sense all angles of a triangle add up to 180 and the ratio of angles is 3:3:6 the we can find the angle with the equation x+x+2x=180

Simplify.

4x=180

Solve by dividing 4 from both sides

x=45

so it is a 45, 45, 90 triangle. (right triangle because the 90 and icoceles because other 2 angles are congruent so option 5 is correct)

m∠J= 45°

m∠K= 45° (Option 1 is correct)

m∠L= 90° (Option 6 is correct)

4.

I honestly don't see how you can solve this without making assumptions so I will make assumptions.

Assuming the whole figure is symmetrical vertically ∠1 is congruent to the same spot on the right side of the shape. This angle would be supplementary to the angle of the angle outside of the shape adjacent on the right making the angle (which is corresponding, therefore congruent to ∠2) 133°.

8 0
2 years ago
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