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Ratling [72]
4 years ago
9

A pressure cooker cooks a lot faster than an ordinary pan by maintaining

Physics
1 answer:
OLga [1]4 years ago
8 0
It is because of pressure cooker exert alot of pressure on foood particles to get quickly food ...


When cooking something wet, like a stew or steamed vegetables, the heat of your cooking is limited to the boiling point of water (100°C). But with the steam's pressure now the boiling point can get as high as 138°C. This higher heat helps the food to cook faster.


Matk as brainliest please

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The energy needed to change an amount of a substance from a solid to a liquid is the
Korvikt [17]

Answer:

Heat or thermal energy!!!

Explanation: When heat is added the particles speed up at rapid rates causing the state of the object to change nd in order to melt it must be heated.

3 0
4 years ago
Which of the following statements is true about the scientific process? The hypothesis is always supported in the end / You can
Pachacha [2.7K]
The correct answer is the statement #3. The statement that says: your hypothesis must be testable, is a true statement about the scientific process. IT will be truly unreasonable and a waste to be doing experiments on a hypothesis that is not even possible to solve.
8 0
3 years ago
Read 2 more answers
g 1. Water flows through a 30.0 cm diameter water pipe at a speed of 3.00 m/s. All of the water in the pipe flows into a smaller
levacccp [35]

Answer:

a) v₂ = 30 m/s

b) m₁ = 12600 kg

c) m₂ = 12600 kg

Explanation:

a)

Using the continuity equation:

A_1v_1 = A_2v_2

where,

A₁ = Area of inlet = π(0.15 m)² = 0.07 m²

A₂ = Area of outlet = π(0.05 m)² = 0.007 m²

v₁ = speed at inlet = 3 m/s

v₂ = speed at outlet = ?

Therefore,

(0.07\ m^2)(3\ m/s)=(0.007\ m^2)v_2\\\\v_2 = \frac{0.21\ m^3/s}{0.007\ m^2}

<u>v₂ = 30 m/s</u>

<u></u>

b)

m_1 = \rho A_1v_1t

where,

m₁ = mass of water flowing in = ?

ρ = density of water = 1000 kg/m³

t = time = 1 min = 60 s

Therefore,

m_1 = (1000\ kg/m^3)(0.07\ m^2)(3\ m/s)(60\ s)\\

<u>m₁ = 12600 kg</u>

<u></u>

c)

m_1 = \rho A_1v_1t

where,

m₂ = mass of water flowing out = ?

ρ = density of water = 1000 kg/m³

t = time = 1 min = 60 s

Therefore,

m_2 = (1000\ kg/m^3)(0.007\ m^2)(30\ m/s)(60\ s)\\

<u>m₂ = 12600 kg</u>

7 0
3 years ago
The pictures represent three different states of matter.
Veronika [31]

ONLY if ur asking for the 3 states of matter it is solid liquid and gas

4 0
4 years ago
(a) Check all of the following that are correct statements, where E stands for γmc2. Read each statement very carefully to make
Reil [10]

Answer:

V=9.60m/s

Attached is the solution

5 0
3 years ago
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