Answer:
Step-by-step explanation:
(1,6)
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Answer:
They subtracted 2x from both sides.
Step-by-step explanation:
They removed 2x from each side because in order to find x it will have to be removed on one side. Since 2x - 2x = 0 it is 2x is out of the equation for the right side and on the left side -2x -(-4x) = -6x which means that there is one x variable left in the equation thus making it solvable.
It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
So, First we will do the sum of the three given polynomials,
Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
Now, we can perform the subtraction,
∴ Required difference
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
Part A is irrational, but Parts B and C are both rational.
We know that Part A is irrational because an irrational number added to a rational number is still irrational. Also, an irrational number multiplied by a rational number is still irrational.
With Part B, we have an irrational number in the square root of 7. However, it is then squared to give us 7. This leaves us with 7 times a^2 which is rational. Two rational numbers multiplied still give us a rational number.
Finally, Part C only involves adding and multiplying rational numbers. Since that can only yield rational numbers, it must be rational.
