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GuDViN [60]
2 years ago
5

When weather starts to average out in a pattern over many years, like 30 years, scientists can calculate the average weather con

ditions in a place or region. This is what we call climate. Remember that weather is usually the way we describe the conditions over an hour, day, or week, or maybe even a significant storm, but climate is how we describe a place’s long-term weather conditions.
What are ways you would describe our climate and how it compares to the climate in other parts of the country?
Chemistry
1 answer:
meriva2 years ago
6 0

Answer:

the earth is different in all places

Explanation:

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What is a colligative property?
V125BC [204]
<span>Colligative properties are properties of solutions that depend on the number of molecules [or ions] in a given volume of solvent and not on the properties (e.g. size or mass) of the compound. Colligative properties include: lowering of vapor pressure; elevation of boiling point; depression of freezing point and osmotic pressure.</span>
6 0
3 years ago
Ian uses litmus paper to determine whether five unknown solutions are acids or bases. The litmus paper turns red when the pH is
Roman55 [17]

Answer: b

explanation: i had the question on a test and got it right.

3 0
3 years ago
In the front of the room, there is a bottle that contains a 32.00 g sample of sulfur. This is
Vera_Pavlovna [14]
6.02x10^23 atoms is the answer
8 0
3 years ago
What mass of sucrose needs to be dissolved in 540 g of water in order to prepare a 15% by mass solution.
Lilit [14]

Answer:

95.3g

Explanation:

Given parameters:

Mass of water  = 540g

Percentage by mass of solution = 15%

Unknown:

Mass of sucrose = ?

Solution;

To solve this problem, we must understand that a solution is made up of solute dissolved in a solvent. A solute is the solid dissolved in another. The solvent is the is dissolving medium;

    Percentage by mass of solute in solution = \frac{Mass of solute}{Mass of solution}  x 100

Mass of solution  = mass of water + Mass of sucrose  = 540 + M

  where M is the mass of sucrose;

therefore;

                 \frac{M}{540 + M }  x 100   = 15

   Solving for M gives 95.3g

Mass of sucrose is 95.3g

5 0
2 years ago
How would you prepare 1.00 L of a 0.50 M solution of each of the following?
Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated  12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

n_1=n_2

Which can also be written in terms of concentrations and volumes:

M_1V_1=M_2V_2

Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:

V_1=\frac{M_2V_2}{M_1} \\\\V_1=\frac{1.00L*0.5M}{12M}\\ \\V_1=0.0417L=41.7mL

It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.

Best regards.

6 0
3 years ago
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