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3 years ago

Label each element in the chemical reaction below with the correct oxidation state

Chemistry

1 answer:

natka813 [3]3 years ago

3 0

Answer:

N = -3

H = +1

O = -2

Cl = +1

Explanation:

The balanced Equation of the reaction above is:

NH3 + 3HOCl ----> NCl3 + 3H2O

Where NH3 is ammonia;

HOCl is Oxochlorate (I) acid

NCl3 is nitrogen trichloride

H2O is water

Nitrogen in both Ammonia and Nitrogen trichloride has an oxidation state of -3. It shares three electrons with each of the three atoms of hydrogen and chlorine

Hydrogen in both Oxochlorate (I) acid and in water has an oxidation state of +1. Each atom shares an election with oxyen in both compounds.

Oxygen in both Oxochlorate (I) acid and water has an oxidation state of -2. Each atom shares two electrons with neighboring atoms; in HOCl, it shares with chlorine and hydrogen, while in H2O, it shares with two atoms of hydrogen.

Chlorine in both Oxochlorate (i) acid and Nitrogen trichloride has an oxidation state of +1. It shares an electron with each of it's neighboring bonded atoms.

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6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/

Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

$A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}$

(b) Percent transmission

$A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}$

7) Absorbance

$A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}$

8 0

3 years ago

A chemical ____ is a process in which some substances change chemically into different substances

garik1379 [7]

Is reaction a choice?

6 0

1 year ago

Read 2 more answers

Balance the following chemical equation. CCl4 -> ___ C+ ___ Cl2

Bingel [31]

Answer:

Explanation:

CCl4 => C + 2Cl2

6 0

2 years ago

Can cells that are haploid (single set of chromosomes ) undergo meiosis

Dima020 [189]

Answer:

Yes they can

Haploid cells are mostly sex cells and these cells usually undergo meiosis.

Hope this helps.

5 0

3 years ago

139%

GaryK [48]

Answer:

The percent composition of this compound is 94%

Explanation:

The reaction can be formed as

$2 \mathrm{Fe}+3 \mathrm{Cl}_{2} \rightarrow 2 \mathrm{FeCl}_{3}$

$\frac{\text { Weight of } \mathrm{Cl}_{2}}{\text { 3* Molar Mass of } \mathrm{Cl}_{2}}=\frac{\text { Weight of } \mathrm{Fe}}{2 * \text { Molar Mass of Fe }}$

$\frac{\text { Weight of } \mathrm{Cl}_{2}}{3 *(2 * 35.5)}=\frac{3.56}{2 * 55.8}$

$\text { Weight of } C l_{2}=\frac{3.56 * 3 * 71}{2 * 55.8}=6.79 \mathrm{g}$

$\mathrm{n}\left(\mathrm{Cl}_{2}\right)=\mathrm{m}\left(\mathrm{Cl}_{2}\right) / \mathrm{M}\left(\mathrm{Cl}_{2}\right)=6.79 / 71=0.1 \mathrm{m}$

$\mathrm{n}(\mathrm{Fe})=\mathrm{m}(\mathrm{Fe}) / \mathrm{M}(\mathrm{Fe})=3.56 / 55.8=0.06 \mathrm{m}$

Based on no. of iron reacted,

$\mathrm{n}(\text { moles of } \mathrm{Fe})=\mathrm{n}\left(\text { moles of } \mathrm{FeCl}_{3}\right)$

n = m/M

$\mathrm{m}\left(\mathrm{FeCl}_{3}\right)=\mathrm{n}^{*} \mathrm{M}=0.06^{*} 162.5=9.75 \mathrm{g}$

% composition of $FeCl_3$

= $(9.75 / 10.39)^{*} 100$

= 94%

6 0

3 years ago