While john is traveling along a straight in interstate highway, he notices that the mile marker reads 242 mm. John travels until
1 answer:
Complete Question
While john is traveling along a straight in interstate highway, he notices that the mile marker reads 242 km. John travels until he reaches the 147 km marker and then retraces his path to the 161 km marker. What is John's resultant displacement from the 242 km marker? How far has he traveled answer in units of km
Answer:
The resultant displacement
The total distance traveled by john is
Explanation:
From the question we are told that
The first position of john from the finish point is
The second position of john from the finish point is
The third position of john from the finish point is
Generally the displacement from the 242 km marker is mathematically represented as
Here we used instead of
because
is further than
from the finish point
=>
Generally the total distance traveled by John is mathematically evaluated as
=>
=>
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Answer:
t = 123.59s
Explanation:
For the launch pad section:
Vf = Vo + a*t where Vo=0.
Vf = 35*25 = 875m/s
The distance traveled during the launch:
Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.
where d= 10937.5m; Vo=875m/s.
Solving for t:
t1 = -11.093s t2 = 98.59s
So, the total time of flight will be:
The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.
- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
So, the final momentum must be zero as well:
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
From which
- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is
. Therefore, the total kinetic energy before the collision is
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
(1)
But the final kinetic energy, Kf, is also
Substituting as we found in the conservation of momentum, this becomes
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write
Therefore, the two final speeds of the balls are
This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.
- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
So, the final momentum must be zero as well:
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
From which
- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
But the final kinetic energy, Kf, is also
Substituting
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write
Therefore, the two final speeds of the balls are
This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.
Answer:
Explanation:
Given
Radius of A is twice of B i.e.
Also Potential of both sphere is same
thus
(b)Ratio of
Electric Field is given by
thus ----1
----2
Divide 2 by 1