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3 years ago

3. Check that the dimensions of both side of the equations below are agreeing to each other:

Physics

1 answer:

Reptile [31]3 years ago

4 0

Answer:

b is the answer of that question answer sapai

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A hollow sphere of radius 0.200 m, with rotational inertia I = 0.0484 kg·m2 about a line through its center of mass, rolls witho

d1i1m1o1n [39]

Answer:

Part a)

$KE_r = 8 J$

Part b)

v = 3.64 m/s

Part c)

$KE_f = 12.7 J$

Part d)

$v = 2.9 m/s$

Explanation:

As we know that moment of inertia of hollow sphere is given as

$I = \frac{2}{3}mR^2$

here we know that

$I = 0.0484 kg m^2$

R = 0.200 m

now we have

$0.0484 = \frac{2}{3}m(0.200)^2$

$m = 1.815 kg$

now we know that total Kinetic energy is given as

$KE = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2$

$KE = \frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{R})^2$

$20 = \frac{1}{2}(1.815)v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2$

$20 = 1.5125 v^2$

$v = 3.64 m/s$

Part a)

Now initial rotational kinetic energy is given as

$KE_r = \frac{1}{2}I(\frac{v}{R})^2$

$KE_r = \frac{1}{2}(0.0484)(\frac{3.64}{0.200})^2$

$KE_r = 8 J$

Part b)

speed of the sphere is given as

v = 3.64 m/s

Part c)

By energy conservation of the rolling sphere we can say

$mgh = (KE_i) - KE_f$

$1.815(9.8)(0.900sin27.1) = 20- KE_f$

$7.30 = 20 - KE_f$

$KE_f = 12.7 J$

Part d)

Now we know that

$\frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{r})^2 = 12.7$

$\frac{1}{2}(1.815) v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2 = 12.7$

$1.5125 v^2 = 12.7$

$v = 2.9 m/s$

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3 years ago

Find the initial velocity

Alla [95]

Answer:

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Explanation:

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3 years ago

Explain the difference between vector and scalar quantities

Rom4ik [11]

Answer:

vector quantity have both magnitude and direction but scalar quantities have only magnitude

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2 years ago

An attractive force of 7.2 N occurs between two charges that are 0.20 m apart. If one charge is 4.0 μC, what is the other charge

VikaD [51]

F = ko *Q_1 * Q_2 / d^2

Q_2 = F*d^2 / [ko*Q_1] = 7.2 N * (0.2m)^2 / [9.0 x 10^9 N/m^2C^2 * 4.0 x 10^-6C] = 8x10^-6C = 8 microC

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3 years ago

Please help on this one?

svetlana [45]

It should be answer d?

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3 years ago