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marin [14]
3 years ago
7

The relationship between gas pressure and gas volume is described by ________.

Physics
2 answers:
madam [21]3 years ago
8 0
Answer: A
Hope this helped
Tasya [4]3 years ago
5 0

The relationship between gas pressure and gas volume is described by ________.

A) Boyle's law

B) Henry's law

C) Dalton's law

D) Charles' law

Answer:

<u><em>A) Boyle's law</em></u>

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The angular velocity of a process control motor is (13−12t2) rad/s, where t is in seconds. Part A At what time does the motor re
mihalych1998 [28]

Answer:

Explanation:

Given

\omega =13-\frac{1}{2}\cdot t^2

Motor reverse its direction when \omega =0

13-0.5t^2=0

26=t^2

t=\sqrt{26}=5.099\approx 5.1 s

(b)

\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega

\int d\theta =\int_{0}^{5.1}\omega dt

\int d\theta =\int_{0}^{t}(13-.05t^2)dt

\theta =(13t-0.1667\times t^3)_0^{5.1}

\theta =44.192^{\circ}

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3 years ago
Determine the current I flowing through a solenoid, if the magnetic flux inside its core is found to be 1.30 10-4 Wb. The radius
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Explanation: Please see the attachments below

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3 years ago
19. A 0.0340 kg bullet traveling at 120 m/s embeds itself in a 1.24 kg wooden block which
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Answer: x ≈ 36.3 cm

Explanation:

Conservation of momentum during the collision

0.0340(120) + 1.24(0) = (0.0340 + 1.24) v

v = 3.2025 m/s

The kinetic energy of the block/bullet mass will convert to spring potential

½kx² = ½mv²

x = √(mv²/k)

x = √(1.274(3.2025²) / 99.0)

x = 0.363293... ≈ 36.3 cm

3 0
3 years ago
1) A satellite in orbit around Earth is in uniform circular motion. What is the angle between the velocity vector and accelerati
artcher [175]

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1 year ago
A scientist wants to model an internal organ with connective tissue as a mass on a spring. The mass of the organ is 2.0 kg, and
vichka [17]

Answer:

Spring constant, k = 5483.11 N/m

Explanation:

It is given that,

Mass of the organ, m = 2 kg

The natural period of oscillation is, T = 0.12 s

Let k is the spring constant for the spring in the scientist's model. The period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

k=\dfrac{4\pi^2 m}{T^2}

k=\dfrac{4\pi^2 \times 2\ kg}{(0.12\ s)^2}

k = 5483.11 N/m

So, the  spring constant for the spring in the scientist's model is 5483.11 N/m.

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3 years ago
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