Answer:
The object is most likely to be a (distant) galaxy
Explanation:
Distance of galaxies are often calculated based on the unit of light year.
The abbreviation, mpc which translates to mega parsec
A mega parsec is equivalent to 3.3 light years.
So, if the astronomer sighted the object from a distance of 28mpc which is equivalent to 28 * 3.3 light-years (92.4 light years); the object is most likely to be a galaxy; a distant galaxy
The final temperature of the gas given the data from the question is 1527 °C
<h3>Data obtained from the question</h3>
- Initial volume (V₁) = V
- Initial temperature (T₁) = 27 °C = 27 + 273 = 300 K
- Final volume (V₂) = 6V
- Final temperature (T₂) =?
<h3>How to determine the new temperature </h3>
The final temperature of the gas can be obtained by using the Charles' law equation as illustrated below:
V₁ / T₁ = V₂ / T₂
V / 300 = 6V / T₂
Cross multiply
V × T₂ = 300 × 6V
Divide both side by V
T₂ = (300 × 6V) / V
T₂ = 1800 K
Subtract 273 from 1800 K to express in degree celsius
T₂ = 1800 – 273
T₂ = 1527 °C
Learn more about gas laws:
brainly.com/question/6844441
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Answer:
<h2>a</h2><h2> move with an increasing velocity</h2>
Answer:
I have no idea.
Explanation:
I just wanted to tell you I absolutely read this wrong.
