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Julli [10]
3 years ago
5

Construct a triangle ABC if AB = 4 cm, BC = 5 cm and Y = 30 °, then enter a circle​

Mathematics
2 answers:
Alika [10]3 years ago
6 0
The answer is CBD.. the one i got in diss bluhnt
victus00 [196]3 years ago
3 0

Answer:

Refer to the attachment \Huge {\nearrow}

<h3>Can't understand diagram? Don't worry </h3>
  • See the Latex diagram coded below on web
<h3><u>Diagram</u><u>:</u><u>-</u>\Huge {\downarrow}</h3>

\setlength{\unitlength}{1cm}\begin{picture}(20,15)\thicklines\qbezier (1,0)(1,0)(7,0)\qbezier(1,0)(1,0)(2,3)\qbezier (7,0)(7,0)(2,3)\put (0.5,-0.2){\sf X}\put(7.1,-0.2){\sf Y}\put(2,3.2){\sf Z}\end{picture}

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What are the geometric means of 5 and 15
Phantasy [73]

Answer:

2√15

Step-by-step explanation:

7 0
3 years ago
How many six-digit odd numbers are possible if the left digit cannot be zero?
melisa1 [442]
We are asked for the number of <span>six-digit odd numbers that can be formed. the left-most digit should not be zero because it make the number -five digit already. An odd number ends only in 1, 3, 5, 7 and 9. Using counting, the 6th digit can only have 5 numbers, the 5th, 4th, 3rd, and 2nd can have, 10 numbers. The first number can only have 9 numbers. Hence the total number is 450,000</span>
6 0
3 years ago
Can somebody tell me if I did it right I’m not sure how I’m supposed to find the distance?
Salsk061 [2.6K]

Answer:

6.4 units

Step-by-step explanation:

Use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(8-3)^2+(-3-(-7))^2}

d=\sqrt{(5)^2+(4)^2}

d=\sqrt{25+16}

d=\sqrt{41}

d=6.4

Therefore, the distance between (3,-7) and (8,-3) is 6.4 units

Hopefully, this was helpful!

5 0
3 years ago
Read 2 more answers
Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of
forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

n = 120, \pi = \frac{58}{120} = 0.4833

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0
3 years ago
A standard oil drum is a cylinder with a volume of approximately 218.276 liters (or 0.218276 cubic meters). The cost of producin
Arte-miy333 [17]

Answer:

r = 2,85 feet

h = 8,56 feet

Step-by-step explanation:

Area of two circular caps (m ^(2)) : 2* pi* r^(2) (where  r is the radius of circular cap)     Area of wall (m ^(2))  is 2*pi*r*h (where h is the height of drum)

V= pi*r^(2)*h           so  h=V/pi*r^(2)   (1)

Cost in $:

Cost of wall 25 $/m^(2) plus 10% for manufacturing so:

C(w) = 27,5*2*pi*r*h $/square feet

Cost of (both top and bottom cap) = 2*40,97*pi* r^(2) so:

C(caps) = 257,29* r^(2) $/squaer feet

Total cost of cylnder = cost of wall + cost of caps

Total cost f cylinder: F(c)= 55*pi*r*h+257,29* r^(2)

F(c) = 172,7*r*h + 257,29*r^(2)         F(c)  is F(r)

Since from (1) we have h=218,276/pi*r^(2)  

F(r) = (172,7)*r*(69,514)/r^(2) +257,29*r^(2)           F(c) = 12005/r + 257,29*r^(2)

Taken the first dervative

F´(r)= -12005*(1)/r^(2) +2*257,29*r         F´(r) =  -12005*(1)/r^(2) +514,58*r

f F´(r) = 0          -12005*(1)/r^(2) + 514,58*r =0

-120005 + 514,58*^(3) = 0          514,58*^(3) = 12005      r =cubic root (23,32)

r = 2,85 ft

if we replace this value en F(r) we can see F(r) tend to infinite both when r tend to 0 and when r tends to infnite so there is a minimun for the functon

r = 2,85 ft    and   h = 8,56 ft

5 0
3 years ago
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