To determine the mass of each compound, we need to convert them into units of moles first. We use avogadros number to do this and use the molar mass of the compounds to convert to mass.
<span>3.01 × 1023 molecules H2O ( 1 mole / 6.022x10^23 kg) (18.02 g / 1 mole) = 9.01 g
8.32 × 1020 formula units CaBr2 </span>( 1 mole / 6.022x10^23 kg) (199.89 g / 1 mole) = 0.28 g<span>
1.93 × 1026 molecules XeF6 </span>( 1 mole / 6.022x10^23 kg) (245.28 g / 1 mole) = 78610.16 g
C. The Seasons change during the year.
Would be the correct answer.
Answer:
300 K
General Formulas and Concepts:
<u>Atomic Structure</u>
<u>Gas Laws</u>
Ideal Gas Law: PV = nRT
- <em>P</em> is pressure
- <em>V</em> is volume
- <em>n</em> is moles
- <em>R</em> is gas constant
- <em>T</em> is temperature
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>n</em> = 0.5 mol N₂
[Given] <em>V</em> = 6 L
[Given] <em>P</em> = 2 atm
[Given] <em>R</em> = 0.0821 L · atm · mol⁻¹ · K⁻¹
[Solve] <em>T</em>
<em />
<u>Step 2: Solve for </u><em><u>T</u></em>
- Substitute in variables [Ideal Gas Law]: (2 atm)(6 L) = (0.5 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)T
- Multiply [Cancel out units]: 12 atm · L = (0.04105 L · atm · K⁻¹)T
- Isolate <em>T</em> [Cancel out units]: 292.326 K = T
- Rewrite: T = 292.326 K
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 1 sig fig as our lowest.</em>
292.326 K ≈ 300 K
Answer:
4.
Explanation:
It's neither qualitative and quantitative. Qualitative is speculation on quality, and quantitative is speculation on quantity, or the amount of something.
