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Bogdan [553]
3 years ago
5

Define Physical and Chemical change

Chemistry
1 answer:
vlada-n [284]3 years ago
7 0

Answer:

Explanation:

Chemical is when there is a change of color odor or temperature rises

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The process by which particles in a solution spread out evenly is called?
padilas [110]

Answer:

this is your answer.....

7 0
3 years ago
How to round the decimal 4.15 to the hundredths place?​
gladu [14]

Answer:4.15 is already in the hundreths place so you are good!

if it was 4.155 then you would round it to 4.16 but its NOT that so the answer IS 4.15

Explanation:

8 0
2 years ago
calculate the volume that will be occupied by 350 ml of oxygen measured at 720 mm hg, when the pressure changed to 630 mm hg
likoan [24]

Answer:

406.45mL

Explanation:

The following data were obtained from the question:

V1 = 350mL

P1 = 720mmHg

P2 = 630mmHg

V2 =?

The new volume can be obtain as follows:

P1V1 = P2V2

720 x 350 = 620 x v2

Divide both side by 620

V2 = (720 x 350) /620

V2 = 406.45mL

The new volume of the gas is 406.45mL

8 0
3 years ago
Question<br> What is the molarity of a 400 mL solution containing 0.60 moles of NaCl?
Mumz [18]

Answer:

0.24 M

Explanation:

Molarity = Moles solute / Liters solution

Step 1: Identify variables

400 mL = Liters solution

0.60 moles = Moles solute

Step 2: Identify conversions

1 L = 1000 mL

Step 3: Convert mL to L

400mL(1 L/1000mL) = 0.4 L

Step 4: Find molarity

M = (0.4 L)(0.60 mol) = 0.24 M

6 0
3 years ago
In the molecules below, areas that have a partial negative charge are pink and areas that have a partial positive charge are blu
Kaylis [27]

Answer:

Dipole-dipole interactions

Step-by-step explanation:

Each molecule consists of <em>two different elements</em>.

Thus, each molecule has permanent <em>bond dipoles</em>.

The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.

"Covalent bonds" is <em>wrong,</em> because there are no bonds between the two molecules.

There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.

4 0
3 years ago
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