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Vera_Pavlovna [14]
3 years ago
9

The molar mass of oxygen(O) is 32g. What is the mass of 1.05*10^25 molecules of O²

Chemistry
1 answer:
Vaselesa [24]3 years ago
4 0

Answer:

Hope that will help you

Explanation:

Text me for more answers

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What is the total number of moles represented by 20 grams of CACO3
Nutka1998 [239]

Answer:

B. 0.2.

Explanation:

  • We can use the relation:

<em>n = mass/molar mass</em>

mass of CaCO₃ = 20 g, molar mass of CaCO₃ = 100.0869 g/mol.

<em>∴ n = mass/molar mass = </em>(20 g)/(100.0869 g/mol) <em>= 0.1998 ≅ 0.2 mol.</em>

<em></em>

<em>So, the right choice is: B. 0.2.</em>

8 0
3 years ago
Як визначити амфотерний, луг чи основний елемент в хімії. Коли назви даєш, то пишеш наприклад CuSO4 - амф, купрум сульфат. Чому
Leno4ka [110]
What? Please write in Spanish or English
7 0
4 years ago
What type of substance reacts with limestone (CaCO3) and produces carbon dioxide gas?
Anestetic [448]
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3 0
4 years ago
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Lab 27. stoichiometry and chemical reactions: which balanced chemical equation best represents the thermal decomposition of sodi
Cloud [144]
Answer:
             Sodium Bicarbonate on decomposition produces Carbon dioxide gas and Water vapors.

<span>                       2 NaHCO</span>₂<span> </span> →<span>  Na</span>₂<span>CO</span>₃<span> (s)  </span>+ <span> CO</span>₂<span> (g)  +  H</span>₂<span>O (g)
</span>
Explanation:
                   Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.
5 0
3 years ago
(chem) which is more concentrated: 45.0 grams of HCOOH dissolved in 189 mL of water or 1.5 moles of CH↓2COOH dissolved in twice
Liula [17]

Answer:

CH3COOH would be more concentrated

Explanation:

The higher the concentration value, the more concentrated it is.

The relationship between concentration, moles and volume is given by the equation;

Concentration = No of moles / Volume

5.0 grams of HCOOH dissolved in 189 mL of water

Number of moles = Mass / Molar mass = 5 / 46.03 = 0.1086 mol

Concentration = 0.1086 / 0.189 = 0.5746 mol/L

1.5 moles of CH3COOH dissolved in twice as much water

Volume = 2 * 189 = 378 ml = 0.378 L

Concentration = 1.5 / 0.378 = 3.9683 mol/L

Comparing both concentration values;

CH3COOH would be more concentrated

6 0
3 years ago
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