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3 years ago

The molar mass of oxygen(O) is 32g. What is the mass of 1.05*10^25 molecules of O²

Chemistry

1 answer:

Vaselesa [24]3 years ago

4 0

Answer:

Hope that will help you

Explanation:

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how do i word a formal letter to a teacher saying i didn't pay attention during the science lessons and i now have no idea what

Allushta [10]

Explanation:

Hello mr/mrs (name) I unfortunately couldn't pay attention to the class due to some issues I had therefore I don't know what we are doing in class

Hello mr/mrs (name) I could understand what we were doing in class I would like it if you could break it down more or explain better to me

OR just say something it had something to do with your internet such as

Hello mr/mrs (name) I didn't understand what you were saying during our class due to some of my internet issues I was have throughout the day. I hope you can explain what we did during the class.

Those may be some of my excuses I've used before

they have worked for me:)

I don't know if that helped?:/

8 0

3 years ago

A solution of aminoheptanoic acid, H2N-(CH2).COOH, in m-cresol at a concentration of 3.3 mol amino acid per kg of solution is po

garik1379 [7]

Explanation:

The given data is as follows.

Concentration = 3.3 mol

Rate constant = $2.74 \times 10^{3} kg/mol min$

Molecular weight = 55000 g/mol

$\tau = C_{A_{0}} \times \int_{0}^{X_{A}} \frac{dX_{A}}{-r_{A}}$

Initial concentration ( $C_{A_{0}}$ ) of aminoheptanoic is 3.3 kg/mol.

$-r_{A} = 2.74 \times 10^{3} kg/mol min$

Hence, putting the given values into the above formula as follows.

$\tau = C_{A_{0}}\times \int_{0}^{X_{A}} \frac{dX_{A}}{-r_{A}}$

= $\frac{3.3}{2.74 \times 10^{3} kg/mol min} [X_{A}]^{0.1}_{0}$

= 120.43 min

Thus, we can conclude that total time required to to form polyamide is 120.43 min.

3 0

3 years ago

Plz help its due today!!!

oksano4ka [1.4K]

Answer:

Explanation: First one is Purple, purple, White.

Hairy, Hairy, Non hairy.

3 0

3 years ago

Read 2 more answers

How many things do controlled experiments attempt to test at one time? 0 1 3 2

Hunter-Best [27]

Answer:

Explanation:

your can only test one thing at a time

5 0

3 years ago

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What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v

ad-work [718]

Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is $\lambda$ .

Formula to calculate thickness of a benzene thin film is as follows.

Optical path length through benzene ( $\lambda$ ) = $2 \times n \times d$

Hence, substituting the given values into the above formula as follows.

Optical path length through benzene = $2 \times n \times d$

d = $\frac{\text{Optical path length through benzene}}{2 \times n}$

= $\frac{\lambda}{2 \times n}$

= $\frac{615 \times 10^{-9}}{2 \times 1.501}$ (as 1 nm = $10^{-9}m$

= 204.9 m

Thus, we can conclude that minimum thickness of benzene is 204.9 m.

4 0

3 years ago