Answer:
24.24%
Step-by-step explanation:
In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12
Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.
or 0.2424 or 24.24%
y = mx + b
I mean, thats the formula? :/
Sub in 5 for x
y=(5)2 -9
y= 10-9
y= 1
500m:2km (change km to m)
500m:2000m (divide by 100)
5m:20m (divide by 5)
1m:4m
Answer:
(x-5/2)(x-9).
x^2-5/2x-5/2x+45/2.
Multiply the number by 2.
which is 2(x^2-5/2x-5/2x+45/2).
2x^2-5x-5x+45.
2x^2-10x+45.