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Alex73 [517]
3 years ago
10

Simplify each expression.

Mathematics
1 answer:
Vlad [161]3 years ago
5 0

Answer:

The answer is:

32x+12y

Step-by-step explanation:

Because 4 times 8 =32 and 4 times 3 =12

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How would I translate this sentence into an equation?
lisov135 [29]

Answer:

w(9-5)

Step-by-step explanation:

3 0
3 years ago
The ratio of the length to the width of a cereal box is 5:4. The length of a cereal box is 60 inches what is the width
tankabanditka [31]
K guys u rly need to learn this stuff instead of relying on google for answers, it's not hard, I promise.

Ratio is 5:4
Which is Length: Width.
We're told the Length (in Inches) is 60.
So ratio = 60: ?

A Ratio is just a simplified version of the actual numbers, k?

So The length 'scale', if you like, will be 60/5. =12.
That means one 'unit' of Ratio stuff = 12.
So then you work out the Width, by doing the Ratio number [4] x The Ratio 'scale' [12].

4 x 12 = 48! It's 48 Inches.
3 0
3 years ago
Which arc is a minor arc?
zepelin [54]

Answer:

The arc PS would be a minor arc

Step-by-step explanation:

As a minor arc is one that is less that 180 degrees, it would be the only viable solution.

Line SO is not an arc, so it cannot be chosen

the measures of arcs SQ and PSR are each 180 degress, so they would not be minor.

8 0
3 years ago
Read 2 more answers
Tell which metric unit you would probably use to measure each item
MrMuchimi
1. height of a shade = meters
2. milligrams
3.milliliter
4. grams 

3 0
3 years ago
What are the foci of the hyperbola with equation 5y^2-4x^2=20?
shusha [124]
The foci of the hyperbola with equation 5y^2-4x^2=20 will be given as follows:
divide each term by 20
(5y^2)/20-(4x^2)/20=20/20
simplifying gives us:
y^2/4-x^2/5=1
This follows the standard form of the hyperbola
(y-k)²/a²-(x-h)²/b²=1
thus
a=2, b=√5 , k=0, h=0
Next we find c, the distance from the center to a focus.
√(a²+b²)
=√(2²+(√5)²)
=√(4+5)
=√9
=3
the focus of the hyperbola is found using formula:
(h.h+k)
substituting our values we get:
(0,3)
The second focus of the hyperbola can be found by subtracting c from k
(h,k-c)
substituting our values we obtain:
(0,-3)

Thus we have two foci
(0,3) and (0,-3)
5 0
3 years ago
Read 2 more answers
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