Answer:
So if we are solving for x and y. First we need to subtract both equations. We take each equation and put in parenthesis and subtract.
y-y = (3x+7)-(-2x-3) =
0 = 3x+7+2x+3
0 = 5x+10
-10 = 5x
-2 = x.
Now we need to solve for y.
Plug it in for the first equation. -2*3+7 = -6+7 = 1
Test if we are correct and try in the second equation.
-2*-2-3 = 4-3 = 1
<u>x = -2</u>
<u>y = 1</u>
Answer:
A.
Step-by-step explanation:
The center is at (0, -6) so the equation is:
(x - 0)^2 + ( y + 6)^2 = r^2
x^2 + (y + 6)^2 = r^2
r^2 = 11
Answer is x^2 + (y + 6)^2 = 11.
Answer:
As with any function, the domain of a quadratic function f(x) is the set of x -values for which the function is defined, and the range is the set of all the output values (values of f ). Quadratic functions generally have the whole real line as their domain: any x is a legitimate input. The vertex will be the minimum (lowest point) of the graph if and the maximum (highest point) of the graph if
4 times 8 tenths
1/10=1 tenth
8/10=8 tenths
4 times 8/10
4/1 times 8/10
(4 times 8)/(1 times 10)
32/10
16/5
5/5+5/5+5/5+1/5
1+1+1+1/5
3+1/5
3 and 1/5
Answer:
81.68
Step-by-step explanation:
The radius is half the diameter so the radius is 13. 13 times pi times 2 equals 81.68.
