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pantera1 [17]
3 years ago
13

PLEASE HELP ME

Mathematics
2 answers:
Maru [420]3 years ago
3 0

Answer:

Option C Both gift boxes have the same length for a given volume

Step-by-step explanation:

step 1

<u>David's gift box</u>

Calculate the side length of the box for a given volume

we have

f(x)=\sqrt[3]{x-1}

For (x-1)=2\ ft^{3} ------> f(x)=\sqrt[3]{2}=1.26\ ft

For (x-1)=4\ ft^{3} ------> f(x)=\sqrt[3]{4}=1.59\ ft

For (x-1)=6\ ft^{3} ------> f(x)=\sqrt[3]{6}=1.82\ ft

For (x-1)=10\ ft^{3} ------> f(x)=\sqrt[3]{10}=2.15\ ft

therefore

Both gift boxes have the same length for a given volume

prohojiy [21]3 years ago
3 0

Answer:

The answer would be Ronald. Also this is for plato too.

Step-by-step explanation:

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−5.5x + 0.46 = −3.94
aliina [53]

Answer:

x= 0.78 (rounded to the hundredth)

Step-by-step explanation:

-5.5x + 0.46 = -3.94

You need to isolate x so the easiest thing to do is subtract 0.46 and move it to the other side of the equal sign.

-5.5x= -3.84 - 0.46

-5.5x = -4.3

divide -5.5 to get x alone

x= -4.3/-5.5

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7 0
3 years ago
The scientist creates an equation that models her data for each tree so that she can predict the diameter in the future. Complet
otez555 [7]

Answer:

y = 0.3X + 18.3

Step-by-step explanation:

Given that data :

x = year ;

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Year ________trunk diameter

1 __ 18.6

3 __ 19.2

5 __ 19.8

7 __ 20.4

9 ___21.0

11 __ 21.6

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Using the linear regression calculator :

The linear equation obtained is :

y = 0.3X + 18.3

Where ;

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8 0
3 years ago
The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu
m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. \mu=23.50

\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0
3 years ago
Denise is selling roses. She sold 3 for $5 and 5 for $7. What will Denise charge for 12 roses if she keeps selling roses at the
Vlada [557]

Answer:

14$

Step-by-step explanation:

3 0
3 years ago
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Oduvanchick [21]
F(0) = -3(0) + 7
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3 years ago
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