3 years ago

I NEED THIS A SOON AS POSSIBLE

2 answers:

6 0

Work is done when spring is extended or compressed. Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.

ludmilkaskok [199]3 years ago

5 0

Answer: c) 1.0 N/m constant spring stretched 0.3 m.

Explanation:

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$F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N$

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