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4 years ago

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To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes t

he kinetic energy change.Choose the best answer to fill in the blank above:a. accelerationb. workc. positiond. potential energy

1 answer:

QveST [7]4 years ago

3 0

Answer:

(c) position

Explanation:

From the work-energy theorem, the workdone by a force on a body causes a change in kinetic energy of the body.

But, remember that the work done (W) by a force (F) on a body is the product of the force and the distance d, moved by the body caused by the force. i.e

W = F x d

This distance is a measure of the position of the body at a given instance.

Therefore, the work done is given by the force as a function of distance (or position).

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A ball bounces changing velocity from vi=15m/s[D] to vf=15m/s[U] in t=0.01s. The balls acceleration is *

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Answer:

Option (A) is correct

Explanation:

a= (vf-vi)/ t

put the values

hence,

a= ( 15-15)/0.01

a=0

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3 years ago

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A pitcher delivers a fast ball with a velocity of 43 m/s to the south. the batter hits the ball and gives it a velocity of 51 m/

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Assuming north as positive direction, the initial and final velocities of the ball are:
$v_i=-43 m/s$ (with negative sign since it is due south)
$v_f=+51 m/s$
the time taken is $t=1.0 ms=0.001 s$ , so the average acceleration of the ball is given by
$a= \frac{v_f-v_i}{t}= \frac{51 m/s-(-43 m/s)}{0.001 s}=9.4 \cdot 10^4 m/s^2$
And the positive sign tells us the direction of the acceleration is north.

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3 years ago

Alli was in the park playing on the equipment. she noticed that on the highest slide she slides down

LUCKY_DIMON [66]

Answer:

Is this answer complete????

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3 years ago

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A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne

kati45 [8]

Answer:

The average emf that will be induced in the wire loop during the extraction process is 37.9 V

Explanation:

The average emf induced can be calculated from the formula

$Emf = -N\frac{\Delta \phi}{\Delta t}$

Where $N$ is the number of turns

$\Delta \phi$ is the change in magnetic flux

$\Delta t$ is the time interval

The change in magnetic flux is given by

$\Delta \phi = \phi _{f} - \phi _{i}$

Where $\phi _{f}$ is the final magnetic flux

and $\phi _{i}$ is the initial magnetic flux

Magnetic flux is given by the formula

$\phi = BAcos(\theta)$

Where $B$ is the magnetic field

$A$ is the area

and $\theta$ is the angle between the magnetic field and the area.

Initially, the magnetic field and the area are pointed in the same direction, that is, $\theta = 0^{o}$

From the question,

B = 1.5 T

and radius = 15.0 cm = 0.15 m

Since it is a circular loop of wire, the area is given by

$A = \pi r^{2}$

∴ $A = \pi (0.15)^{2}$

$A = 0.0225\pi$

∴ $\phi_{i} = (1.5)(0.0225\pi)cos(0^{o} )$

$\phi_{i} = (1.5)(0.0225\pi)$

( NOTE: $cos (0^{o}) = 1$ )

$\phi_{i} = 0.03375\pi$ Wb

For $\phi_{f}$

The field pointed upwards, that is $\theta = 90^{o}$ . Since $cos (90^{o}) = 0$

Then

$\phi_{f} = 0$

Hence,

$\Delta \phi = 0- 0.03375\pi$

$\Delta \phi = - 0.03375\pi$

From the question

$\Delta t = 2.8 ms = 2.8 \times 10^{-3} s$

Here, $N$ = 1

Hence,

$Emf = -N\frac{\Delta \phi}{\Delta t}$ becomes

$Emf = -(1)\frac{-0.03375\pi}{2.8 \times 10^{-3} }$

$Emf = 37.9 V$

Hence, the average emf that will be induced in the wire loop during the extraction process is 37.9 V.

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3 years ago

What conventions are used in SI to indicate units

klemol [59]

Answer:

<u>Conventions used in SI to indicate units are as follows:</u>

Only singular form of units are used. for example: use kg and not kgs.
Do not use full stop after the abbreviations of any unit. for example: do not use kg. or cm.
Use one space between last numeric digit and SI unit. for example: 10 cm, 9 km.
Symbols and words should not be mixed. for example: use Kilogram per cubic and not kilogram/m3.
While writing numerals, only the symbols of the units should be written. for example: use 10 cm and not Ten cm.
Units named after a scientist should be written in small letters. for example: newton, henry.
Degree sign should not be used when the kelvin unit is used. for exmaple: use 37° and not 37°k

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