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Bad White [126]
3 years ago
10

The distance from the earth to a star that has identical apparent and absolute magnitudes is ____ .

Physics
1 answer:
PSYCHO15rus [73]3 years ago
5 0
I think it's distance.
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An athlete stretches a spring an extra 28.6 cm beyond its initial length. how much energy has he transferred to the spring, if t
g100num [7]
PE = 0.5 × k × x²

PE potential Energy
k spring constant
x stretch/compression of the spring
6 0
3 years ago
Please help :)<br> i would rlly appreciate it :)))
algol [13]

Answer:

the answer for that is "A"

6 0
2 years ago
A high diver dives into a swimming pool. His potential energy at the top is 10,000 J (relative to the surface of the pool). What
Semmy [17]

Answer:

Kinetic energy of diver at 90% of the distance to the water is 9000 J

Explanation:

Let d is the distance between the position of the diver and surface of the pool.

Initially, the diver is at rest and only have potential energy which is equal to 10000 J.

As the diver dives towards the pool, its potential energy is converting into kinetic energy due to law of conservation of energy, as total energy of the system remains same.

Energy before diving = Energy during diving

(Potential Energy + Kinetic Energy) =  (Kinetic Energy +  Potential Energy)

When the diver reaches 90% of the distance to the water, its kinetic energy

is 90% to its initial potential energy, as its initial kinetic is zero,i.e.,

K.E. = \frac{90}{100}\times10000

K.E. = 9000 J

6 0
2 years ago
List 3 quantities of waves.
VARVARA [1.3K]
If you mean like electromagnetic waves then, Mico waves, UV rays, and infrared waves
8 0
3 years ago
Read 2 more answers
The temperature of a black body is 500 and its radiation is of wavelength 600 . If the number of oscillators with energy is 100
stiks02 [169]

Answer: An equation is missing in your question below is the missing equation

a) ≈ 8396

b) 150 nm/k

Explanation:

<u>A) Determine the number of Oscillators in the black body</u>

number of oscillators = 8395

attached below is the detailed solution

<u>b) determine the peak wavelength of the black body </u>

Black body temperature = 20,000 K

applying Wien's law / formula

λmax = b / T  ------ ( 1 )

T = 20,000 K

b = 3 * 10^6 nm

∴  λmax = 150 nm/k

4 0
2 years ago
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