PE = 0.5 × k × x²
PE potential Energy
k spring constant
x stretch/compression of the spring
Answer:
the answer for that is "A"
Answer:
Kinetic energy of diver at 90% of the distance to the water is 9000 J
Explanation:
Let d is the distance between the position of the diver and surface of the pool.
Initially, the diver is at rest and only have potential energy which is equal to 10000 J.
As the diver dives towards the pool, its potential energy is converting into kinetic energy due to law of conservation of energy, as total energy of the system remains same.
Energy before diving = Energy during diving
(Potential Energy + Kinetic Energy) = (Kinetic Energy + Potential Energy)
When the diver reaches 90% of the distance to the water, its kinetic energy
is 90% to its initial potential energy, as its initial kinetic is zero,i.e.,
K.E. = 
K.E. = 9000 J
If you mean like electromagnetic waves then, Mico waves, UV rays, and infrared waves
Answer: An equation is missing in your question below is the missing equation
a) ≈ 8396
b) 150 nm/k
Explanation:
<u>A) Determine the number of Oscillators in the black body</u>
number of oscillators = 8395
attached below is the detailed solution
<u>b) determine the peak wavelength of the black body </u>
Black body temperature = 20,000 K
applying Wien's law / formula
λmax = b / T ------ ( 1 )
T = 20,000 K
b = 3 * 10^6 nm
∴ λmax = 150 nm/k