The distance from the earth to a star that has identical apparent and absolute magnitudes is ___

An open system starts with 52 J of mechanical energy. The energy changes

MArishka [77]

Answer:

ITS C 47

Explanation:

5 0

4 years ago

Read 2 more answers

Your boss wants you to advise him about what shape of wheels to use for his son’s pinewood

Morgarella [4.7K]

Answer:

Ring v² = gh

solid wheel (cylinder) v² = 4/3 gh

Explanation:

Let's use conservation of energy to find the speed of the wheels at the bottom of the hill.

starting point. Point before starting movement

Em₀ = mgh

final point. At the bottom of the hill

Em_f = K = ½ m v² + ½ I w²

energy is conserved

Emo = Em_f

mgh = ½ m v² + ½ I w²

angular and linear velocity are related

v = w r

we substitute

mgh = ½ m v² + ½ I v² / r²

mgh = $\frac{1}{2} \ ( m+ \frac{I}{r^2} ) \ v^2$ ½ (m + I / r²) v²

v² = $\frac{2mgh}{m+ \frac{I}{r^2} }$

the moments of inertia are tabulated

Ring

I = mr²

v² = 2 m g h / (m + m)

v² = gh

solid wheel (cylinder)

I = ½ m r²

v² = 2m gh / (m + m / 2)

v² = 4/3 gh

We can see that due to the difference in the moment of inertia of each body it is different, the solid wheel has more speed when it reaches the lower part of the ramp

4 0

3 years ago

What is the length of a spring that has 450J of potential energy and a spring constant of 650N/m?

11111nata11111 [884]

Answer:

Δx = 1.2 m

Explanation:

The CHANGE of spring length) (Δx) can be found using PS = ½kΔx²

Δx = √(2PS/k) = √(2(450)/650) = 1.17669... ≈ 1.2 m

The actual length of the spring is unknown as it varies with material type, construction method, extension or compression, and other variables we have no clue about.

4 0

3 years ago

A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s lat

victus00 [196]

Answer / Explanation

It is worthy to note that the question is incomplete. There is a part of the question that gave us the vale of V₀.

So for proper understanding, the two parts of the question will be highlighted.

A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19s later. You may ignore air resistance.

a) What must the height of the building be for both balls to reach the ground at the same time if (i) V₀ is 6.0 m/s and (ii) V₀ is 9.5 m/s?

b) If Vo is greater than some value Vmax, a value of h does not exist that allows both balls to hit the ground at the same time.

Solve for Vmax

Step Process

a) Where h = 1/2g [ (1/2g - V₀)² ] / [(g - V₀)²]

Where V₀ = 6m/s,

We have,

h = 4.9 [ ( 4.9 - 6)²] / [( 9.8 - 6)²]

= 0.411 m

Where V₀ = 9.5m/s

We have,

h = 4.9 [ ( 4.9 - 9.5)²] / [( 9.8 - 9.5)²]

= 1152 m

b) From the expression above, we got to realise that h is a function of V₀, therefore, the denominator can not be zero.

Consequentially, as V₀ approaches 9.8m/s, h approaches infinity.

Therefore Vₙ = V₀max = 9.8 m/s

4 0

3 years ago

A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during

Alexeev081 [22]

The acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

The given parameters;

initial velocity of the engine, u = 1341 m/s
final velocity of the engine, v = 7600 m/s
time of motion, t = 2 minutes = 2 x 60 s = 120 s

The acceleration of the SRB and main engine is calculated as follows;

$a = \frac{\Delta v}{\Delta t } \\\\a = \frac{7600 - 1341}{2 \times 60 s} \\\\a = 52.16 \ m/s^2$

Thus, the acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

Learn more here:brainly.com/question/17067013

4 0

3 years ago

The distance from the earth to a star that has identical apparent and absolute magnitudes is ____ .