Calculate the work done to push a 200-N object 5-meters

A meter stick moves parallel to its axis with speed of 0.96 c relative to you. What would you measure for the length of the stic

Fed [463]

Answer:

The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

Explanation:

Given that,

Relative speed of stick v= 0.96 c

Speed of light $c= 2.99793\times10^{8}\ m/s$

Proper length of stick = 1 m

We need to calculate the length of the stick

Using formula of length

$\Delta l=\Delta l_{0}\sqrt{(1-\dfrac{v^2}{c^2})}$

Put the value into the formula

$\Delta l=1\sqrt{1-\dfrac{(0.96)^2c^2}{c^2}}$

$\Delta l=1\sqrt{1-(0.96)^2}$

$\Delta l=0.28\ m$

We need to calculate the time the stick take to move

Using formula of time

$t=\dfrac{\Delta l}{v}$

Put the value into the formula

$t=\dfrac{0.28}{0.96\times(2.99793\times10^{8})}$

$t=9.72\times10^{-10}\ sec$

$t=0.97\ ns$

Hence, The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

7 0

3 years ago

Three samples of gas each exert 740. mm Hg in separate 2 L containers. What pressure do they exert if they are all placed in a s

Usimov [2.4K]

According to Dalton's law of partial pressure, the total pressure exerted is simply equal to the sum of the partial pressures of the individual gases. Given that all three samples of gas each exert 740 mmHg, when they are placed in a single 2 L container, they exert a pressure of 2220 mmHg on the container which is the sum of their individual pressures.

5 0

4 years ago

A lens with f = +11cm is paired with a lens with f = −25cm. What is the focal length of the combination?

Zepler [3.9K]

Answer:

19.642 cm

Explanation:

f₁ = Focal length of first lens = 11 cm

f₂ = Focal length of second lens = -25 cm

Combined focal length formula

$\frac{1}{f}=\frac{1}{f_1}+\frac{1}{f_2}\\\Rightarrow \frac{1}{f}=\frac{1}{11}+\frac{1}{-25}\\\Rightarrow \frac{1}{f}=\frac{14}{275}\\\Rightarrow f=\frac{275}{14}\\\Rightarrow f=19.642\ cm$

Combined focal length is 19.642 cm

5 0

3 years ago

Non-Alaskan grizzly bears are indicator species for mountain ecosystems. In the nineteenth century, the grizzly bear nearly went

Marina CMI [18]

Answer:

I think it is C.

Explanation:

I took a 12 question quiz in USA TP and made a 92%. It won't let me see which one I missed though.

Look up habitat fragmentation and think about how well it answers the question given.

5 0

4 years ago

A flat circular plate of copper has a radius of 0.262 m and a mass of 61.5 kg.

Evgesh-ka [11]

Answer:

0.031 m

Explanation:

Density of copper = ρ = 8960 kg/m³

r = Radius = 0.262 m

m = Mass of plate = 61.5 kg

v = Volume of plate = Volume of cylinder = πr²h

$\rho=\frac{m}{v}\\\Rightarrow 8940=\frac{61.5}{\pi r^2h}\\\Rightarrow h=\frac{61.5}{\pi 0.262^2\times 8940}\\\Rightarrow h=0.031\ m$

So, thickness of plate is 0.031 m

5 0

4 years ago