Calculate the work done to push a 200-N object 5-meters

If a car is traveling 60 mph, its tires may have an rpm of 840. How many revolutions do the car’s tires make in one second?

Varvara68 [4.7K]

Forget about the car's speed. You don't need it.

The tires spin 840 rpm. That's 840 <em>Revolutions per Minute</em> .

There are 60 seconds in 1 minute. So something that happens 840 times in 1 minute happens (840 / 60) times every second.

(840 rev per minute) / (60) = <em>14 revs per second</em> .

5 0

2 years ago

Which of the following best defines the science of separating color wavelengths?

Mice21 [21]

Answer: spectroscopy

Spectroscopy is the separation of the light in the different wavelengths and spectrophotometry measures the intensities of the different components of the light to get the composition of substances.

3 0

3 years ago

Read 2 more answers

Homes with multiple bathrooms have outlets connected in series with a red reset button in the system

dybincka [34]

Homes with multiple bathrooms have outlets connected in series with a red reset button in the system. The reason for this circuit design is to prevent electrocution.

<h3>What is red reset button?</h3>

The water heater's reset switch provided on the upper thermostat of an electric water heater. If the button is on, the switch would have tripped and the reset is required.

To prevent any kind of injury or killing of a person by electric shock is called as the electrocution. This can be prevented only by outlets connected in series with a red reset button.

Thus, the reason for this circuit design is to prevent electrocution.

Learn more about red reset button.

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8 0

2 years ago

Human reaction times are worsened by alcohol. How much further (in feet) would a drunk driver's car travel before he hits the br

sweet-ann [11.9K]

Answer:

A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes

Explanation:

Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

where,

Vf = Final Velocity of Car = 0 mi/h

Vi = Initial Velocity of Car = 50 mi/h

a = deceleration of car

s = distance covered

Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.

So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:

s = vt

FOR SOBER DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 0.33 s

s = s₁

Therefore,

s₁ = (73.33 ft/s)(0.33 s)

s₁ = 24.2 ft

FOR DRUNK DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 1 s

s = s₂

Therefore,

s₂ = (73.33 ft/s)(1 s)

s₂ = 73.33 ft

Now, the distance traveled by drunk driver's car further than sober driver's car is given by:

ΔS = s₂ - s₁

ΔS = 73.33 ft - 24.2 ft

6 0

3 years ago

An object of known mass M with speed v0 travels toward a wall. The object collides with it and bounces away from the wall in the

Bingel [31]

Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision

Explanation:

The impulse theorem states that the change in momentum of an object is equal to the impulse, which is the product between the average force applied and the duration of the collision:

$\Delta p = F \Delta t$