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2 years ago

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They don't want place on the school baseball team in the last 9 games one was at bat 28 times and got six hits what is the exper

imental probability that one will get a kid during his next time at that express your answer as a fraction in simplest form

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alex41 [277]2 years ago

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Eisismokistee form is their je. Ejeieiek wowow

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The diagonals of a parallelogram are congruent. Which could be the parallelogram?

kompoz [17]

Consider definitions of <u>parallelogram</u>,<u> trapezoid</u>, <u>rectangle</u>, <u>kite</u> and <u>rhombus</u>.

Parallelogram is a quadrilateral with two pairs of parallel opposite sides.

Trapezoid is a quadrilateral with one pair parallel opposite sides, trapezoid is not parallelogram, so option 1 is false.

Rectangle is a parallelogram with all angles right. Rectangle has diagonals that are congruent. Option 2 is true.

Kite is a quadrilateral with two pairs of congruent adjacent sides. Kite is not parallelogram, so option 3 is false.

Rhombus is a parallelogram with all sides congruent. The diagonals of the rhombus are not congruent, but they are perpindicular bisectors of each other. Option 4 is false.

Answer: correct choice is option 2

5 0

2 years ago

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Show work explain with formulas.

Sedaia [141]

Answer:

$\large\boxed{1.\ a_{44}=481,\ \sum\limits_{n=1}^\infty(11n-3),\ \text{the sum not exist}}$

$\large\boxed{3.\ \sum\limits_{n=1}^{47}(9n+16)=10,904}$

$\large\boxed{4.\ \sum\limits_{n=1}^\infty\bigg(6(2^n)\bigg),\ \text{the sum not exist}}$

Step-by-step explanation:

$1.\\8+19+30+41+...\\\\19-8=11\\30-19=11\\41-30=11\\\\\text{It's an arithmetic series.}\ a_1=8,\ d=11.\\\\\text{The formula for the n-th term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\\text{Substitute:}\\\\a_n=8+(n-1)(11)\qquad\text{use the distributive property}\ a(b-c)=ab-ac\\a_n=8+11n-11\\\boxed{a_n=11n-3}\\\\\text{Calculate the 44th term. Put n = 44 to the formula:}\\\\a_{44}=(11)(44)-3=484-3=481$

$\text{The summation notation:}\\\\\sum\limits_{n=1}^\infty(11n-3)\\\\\text{The sum not exist, because}\ d>1,\ \text{therefore}\ 11n-3\rightarrow\infty.$

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$3.\\25+34+43+52+...+436\\\\34-25=9\\43-34=9\\52-43=9\\\\\text{It's an arithmetic series.}\ a_1=25,\ d=9.\\\\\text{The formula for the n-th term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\\text{Substitute:}\\\\a_n=25+(n-1)(9)\\a_n=25+9n-9\\a_n=9n+16\\\\\text{Calculate which the term of arithmetic series is the number 439.}\\\text{Put}\ a_n=439:\\\\9n+16=439\qquad\text{subtract 16 from both sides}\\9n=423\qquad\text{divide both sides by 9}\\n=47$

$\text{Therefore we have the series in summation notation:}\\\\\sum\limits_{n=1}^{47}(9n+16)\\\\\text{For calculation of the sum we use the formula of a sum of terms}\\\text{of an arithmetic sequence:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\text{Substitute}\ n=47,\ a_1=25,\ a_{47}=439:\\\\S_{47}=\dfrac{25+439}{2}\cdot47=\dfrac{464}{2}\cdot47=232\cdot47=10904\\\\\sum\limits_{n=1}^{47}(9n+16)=10,904$

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$4.\\12+24+48+...\\\\24:12=2\\48:24=2\\\\\text{It's\ a\ geometric series}\ a_1=12,\ r=2.\\\\\text{The formula for the n-th term of a geometic sequence:}\\\\a_n=a_1r^{n-1}\\\\\text{Substitute:}\\\\a_n=(12)(2^{n-1})\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\a_n=(12)\left(\dfrac{2^n}{2^1}\right)\\\\a_n=(6)(2^n)\\\\\text{The summation notation:}\\\\\sum\limits_{n=1}^\infty\bigg(6(2^n)\bigg)\\\\\text{The sum not exist, because}\ r>1,\ \text{therefore}\ 6(2^n)\to\infty$

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2 years ago

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Arlene is showing her work in simplifying −7.9 + 8.2 − 3.4 + 2.1. Identify any errors in her work or in her reasoning. Write fee

NemiM [27]

Step 1 it says Additive inverse, that is not additive inverse. Additive inverse is the opposite of a number. There is no opposite number in the problem. And step 5 is the answer, it shouldn't be simplify. Hope that helps! <span />

5 0

2 years ago

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If sally has 5 apples and Sam has 7 oranges how many oranges are there

KATRIN_1 [288]

There are 7 oranges. You don't need to add the 5 to it because the 5 is apples.

3 0

2 years ago

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Find the value of x.<br> 105° /15xº

pogonyaev

Answer:

X=7

Step-by-step explanation:

I am so sorry if this is not correct. I don´t know why there are 0s next to each number. I hope this helped. Again, I am sorry if this is incorrect

8 0

2 years ago