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Olin [163]
3 years ago
6

A chocolate company makes dark chocolate bars. The quality control department of the company has found that the weights of the c

hocolate bars follow a normal distribution, with a mean of 85 grams and standard deviation of 1.2 grams. To ensure a consistent product, the company has a policy to reject any chocolate bars weighing less than 82.6 grams or more than 87.4 grams. Approximately what percent of chocolate bars are rejected?
a. 0.12%
b. 0.15%
c. 0.30%
d. 2.50%
e. 5.00%
Mathematics
2 answers:
Aleksandr [31]3 years ago
8 0
I believe that it is D.
devlian [24]3 years ago
3 0
D and e i’m pretty sure :)
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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 419 gram setting. It is
Dahasolnce [82]

Answer:

The calculated t- value = 1.09 > 3.19 at 0.025 level of significance

Null hypothesis is rejected

There is sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given the mean of the Population(μ)  = 419 grams

The sample size 'n' =19

Given mean of the sample x⁻ = 412

Given variance of the sample S² = 784

                                                 S = √784 = 28

<u><em>Step(ii)</em></u>:-

<u><em>Null hypothesis: H₀</em></u>: There is no sufficient evidence to support the claim that the bags are underfilled.

<u><em>Alternative hypothesis: H₁:</em></u>

There is sufficient evidence to support the claim that the bags are underfilled.

Test statistic

                     t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

                    t = \frac{412 -419}{\frac{28}{\sqrt{19} } }

                   t = -1.09

                 |t| = |-1.09|

<em>Degrees of freedom   ν = n-1 = 19-1 =18</em>

<em>t₀.₀₂₅ =  3.19</em>

<u><em>Final answer:</em></u><em>-</em>

The calculated t- value = 1.09 > 3.19 at 0.025 level of significance

Null hypothesis is rejected

There is sufficient evidence to support the claim that the bags are underfilled

                   

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