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VARVARA [1.3K]
3 years ago
12

How many electrons can occupy the 4p sublevel of a neutral atom of bromine

Chemistry
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

6

Explanation

every p sublevel holds up to 6 electrons

so the 4p sublevel  must hold up to 6 electonsr

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How do gamma rays differ from a microwave
Alex_Xolod [135]
The difference is the photon energy which the waves use Gamma rays have the highest photon energy and microwaves have a lower photon energy,
5 0
3 years ago
How many atoms make up the products in this equation? NaCl + AgNO3 --> NaNO3 + AgCl
maxonik [38]

Answer:

14

Explanation:

if there is no number behind the element, it counts as one, but if there is, you do 1 times x(whatever the exponent is) and thats how many that one element counts for with atoms. then you just add them all up

8 0
3 years ago
Read 2 more answers
Hydrazine reacts with oxygen according to the following equation: N2H4(g) +O2(g) → N2(g) + 2 H2O(l) How many L of N2, measured a
mihalych1998 [28]

Answer:

V ≈ 646.50 L

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • Reading a Periodic Table
  • Stoichiometry
  • Combined Gas Law: PV = nRT
  • R constant - 62.4 (L · torr)/(mol · K)
  • Kelvin Conversion: K = °C + 273.15

Explanation:

<u>Step 1: Define</u>

RxN:   N₂H₄ (g) + O₂ (g) → N₂ (g) + 2H₂O (l)

Given:   34.9 °C, 755.08 torr, 914.894 g H₂O

<u>Step 2: Identify Conversions</u>

Kelvin Conversion

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

Stoichiometry:   914.894 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} )(\frac{1 \ mol \ N_2}{2 \ mol \ H_2O} ) = 25.3955 mol N₂

Temperature:    34.9 + 273.15 = 308.05 K

<u>Step 4: Find Volume</u>

  1. Substitute variables:                                                                             (755.08 torr)V = (25.3955 mol)(62.4 (L · torr)/(mol · K))(308.05 K)
  2. Multiply:                                                                                                      (755.08 torr)V = 488160 L · torr
  3. Isolate <em>V</em>:                                                                                                          V = 646.502 L

<u>Step 5: Check</u>

<em>We are given 5 sig figs as our lowest. Follow sig fig rules and round.</em>

646.502 L ≈ 646.50 L

6 0
3 years ago
Which of these statements is not true about chemical reaction rates? a Temperature can change a reaction rate. b The amount of r
Umnica [9.8K]

Answer:

The statement that is not true is: 'Temperature does not affect the reaction rate'.  

Explanation:

a) Temperature can change a reaction rate. <u> This is true</u>

Increasing the temperature increases the reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

For example, the time taken to melt a metal will be much higher at a lower temperature but it will decrease as soon as we increase the temperature

b) The amount of reactants can increase the reaction rate.<u> This is true</u>

A higher concentration of reactants leads to more effective collisions per unit time, which leads to an increased reaction rate.

c) Temperature can decrease the reaction rate. <u>This is true </u>

Decreasing the temperature decreases the reaction rates because of the  decrease in the number of high energy collisions. It will result in a slower reaction.

d) Temperature does not affect the reaction rate.  <u>This is not true. </u>

The reaction rate is temperature dependent. The reaction rate increases with higher temperature and decreases with lower temperature.

4 0
3 years ago
The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−
barxatty [35]

Answer:

The reaction will be  non spontaneous at these concentrations.

Explanation:

AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)

Expression for an equilibrium constant K_c:

K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]

Solubility product of the reaction:

K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}

Reaction between Gibb's free energy and equilibrium constant if given as:

\Delta G^o=-2.303\times R\times T\times \log K_c

\Delta G^o=-2.303\times R\times T\times \log K_{sp}

\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]

\Delta G^o=69,117.84 J/mol=69.117 kJ/mol

Gibb's free energy when concentration [Ag^+] = 1.0\times 10^{-2} M and [Br^-] = 1.0\times 10^{-3} M

Reaction quotient of an equilibrium = Q

Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}

\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)

\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])

\Delta G=40.588 kJ/mol

  • For reaction to spontaneous reaction:  \Delta G.
  • For reaction to non spontaneous reaction:  \Delta G>0.

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0
3 years ago
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