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maria [59]
3 years ago
9

if there are 4 grams of reactant,how many grams of product are produced by the chemical reaction. a.0 grams b.2 grams c.4 grams

d.8 grams
Chemistry
1 answer:
Murrr4er [49]3 years ago
5 0
4 grams , mass cannot be created or destroyed. it has to be the same on both sides of the equation
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Which property do metalloids share?
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Metalloids share many similar properties including: They appear to be metal in appearance, but are brittle. They can generally form alloys with metals. Some metalloids such as silicon and germanium become electrical conductors under special conditions. Mark me brainliest please
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3 years ago
Calculate the sublimation pressure of the solid at the melting point of 400.00 K assuming that the enthalpy of sublimation is no
nasty-shy [4]

This question is incomplete, the complete question is;

Tonksite is a solid at 300.00K.  At 300.00 K its enthalpy of sublimation is 66.00 kJ/mol. The sublimation pressure at 300.00 K is 5.00 × 10⁻⁴ atm

Calculate the sublimation pressure of the solid at the melting point of 400.00 K assuming that the enthalpy of sublimation is not a function of temperature.

Answer: the sublimation pressure of the solid at the melting point is  0.3727 atm

Explanation:

Given that;

T1 = 300 K

T2 = 400 K

H_sub = 66 kJ/mol = 66000 J/mol

P1 = 5.00 × 10⁻⁴ atm

p2 = ?

now using the expression

log( p2 / 5.00 × 10⁻⁴ ) = (H_sub / R ×  2.303 ) (( T2 - T1) / T1T2)

now we substitute of given values into the expression

log(p2/p1) = (66000 / 8.314 ×  2.303 ) (( 400 - 300) / 300 × 400 )

p2 = 0.3727 atm

therefore the sublimation pressure of the solid at the melting point is  0.3727 atm

6 0
3 years ago
You can obtain a rough estimate of the size of a molecule with the following simple experiment: Let a droplet of oil spread out
mina [271]

Answer:

The diameter of the oil molecule is 4.4674\times 10^{-8} cm .

Explanation:

Mass of the oil drop = m=9.00\times 10^{-7} kg

Density of the oil drop = d=918 kg/m^3

Volume of the oil drop: v

d=\frac{m}{v}

v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a = 4\pi r^2

a=4\times 3.14\times (0.418 m)^2=2.1945 m^2

Volume of the oil drop = v = Area × thickness

\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x

x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm

The thickness of the oil drop is 4.4674\times 10^{-8} cm and so is the diameter of the molecule.

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Which of the following reactions is endothermic?
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The answer is D

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