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Ostrovityanka [42]
3 years ago
7

The pressure of a mixture of nitrogen, carbon dioxide, and oxygen is 300 kPa. What is the partial pressure of oxygen if the part

ial pressures of the nitrogen and carbon dioxide are 200 kPa and 48 kPa, respectively
Chemistry
1 answer:
Phoenix [80]3 years ago
5 0

Answer:

The partial pressure of oxygen is 52 kPa.

Explanation:

We apply Dalton's law, according to which the sum of the partial pressures of the gases that make up a gaseous mixture is equal to the total pressure of this:

Ptotal = P N2 + P C02 + P 02

300 kPa= 200kPa + 48 kPa + P 02

P 02= 300 kPa - 200kPa - 48 kPa= <em>52 kPa</em>

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Answer:Magnesium (Mg) is a - reactant

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magnesium chloride (MgCI2) is a - product

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Explanation: It’s in my notes

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Explanation:

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2 years ago
What are the two types of collisions? What is the difference between them? Types: a. Types: b. Compare and contrast the two type
mr_godi [17]

Answer:

The two types of collisions are :

Type a)

<u>Elastic collision</u>

Type b)

<u>Inelastic collision</u>

Explanation:

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During collision , the bodies exert force to each other.

Example :

When boxer hits with punches .

When bat hits the ball in cricket match.

So, collision is short duration interaction of two objects. When the objects collides , there is  change in their velocity.

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<u>Compare and contrast the two types</u>

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5 0
3 years ago
A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solutio
-Dominant- [34]

<em>Answer:</em>

  • The concentration of new solution will be 1×10∧-7 M.

<em>Solution:</em>

<em>Data Given </em>

       given mass of fluoxymesterone =16.8mg = 0.0168 g

       molar mass  of fluoxymesterone = 336g/mol

       vol. of fluoxymesterone = 500.0 ml = 0.500 L

      Stock Molarity of  fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M

So applying dilution formula

                   Stock Solution :  New Solution

                                 M1.V1 = M2.V2

       ( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L

     [( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2

     1 × 10∧-7 = M2

<em>Result:</em>

  • The concentration of new solution M2 will be  1 × 10∧-7
3 0
3 years ago
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