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2 years ago

9

How can air pollution affect plants?

1 answer:

GarryVolchara [31]2 years ago

8 0

Answer:

C. air pollution absorbs carbon dioxide

Explanation:

Carbon dioxide's role in the greenhouse effect is a major contributor to air pollution. Radiation and heat emanating from the earth's surface need to be released out into the atmosphere. But because carbon dioxide levels are so high, there is an ozone effect on the ground level.

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Can someone help me with this question please

strojnjashka [21]

Answer:

Are u a boy or a girl so we can form a study group and the answer is C

6 0

2 years ago

Victor pours 100 grams of oil into a beaker filled with 1,000 grams of water. What is the total mass of his mixture?

umka21 [38]

1,100 grams :)
you add the grams of both substances and because they're liquid they don't cancel out

4 0

2 years ago

A gas of 190 mL at a pressure of 74 atm can be expected to change its pressure when its volume changes to 30.0 mL. Express its n

kozerog [31]

Answer : The new pressure of the gas will be, 468.66 atm

Explanation :

Boyle's Law : This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$ (At constant temperature and number of moles)

or,

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure of the gas = 74 atm

$P_2$ = final pressure of the gas = ?

$V_1$ = initial volume of the gas = 190 ml

$V_2$ = final volume of the gas = 30 ml

Now we put all the given values in the above formula, we get the final or new pressure of the gas.

$74atm\times 190ml=P_2\times 30ml$

$P_2=468.66atm$

Therefore, the new pressure of the gas will be, 468.66 atm

4 0

2 years ago

Read 2 more answers

To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber

Phoenix [80]

Answer:

The volume of the gas at given temperature is $1300 cm^3$

Explanation:

$P_1$ = initial pressure of gas = 1 atm

$T_1$ = initial temperature of gas = $0^oC=273.15 K$

$V_1$ = initial volume of gas = $310 cm^3 = 310 mL = 0.310 L$

( $1 cm^3= 1mL$ , 1 mL = 0.001 L)

$P_1V_1=nRT_1$ ..[1]

$P_2$ = final pressure of gas = 2.1 atm

$T_2$ = final temperature of gas = $2,200^oC=273+2200 K=2473.15 K$

$V_2$ = final volume of gas = ?

$P_2V_2=nRT_2$ ..[2]

By dividing [1] and [2] we get combined gas equation :,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}$

Now put all the given values in the above equation, we get:

$V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}$

$V_2=1.3 L=1300 mL= 1300 cm^3$

The volume of the gas at given temperature is $1300 cm^3$

3 0

3 years ago

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Which element was first discovered in space before it was discovered on Earth?

wlad13 [49]

Answer:

carbon

Explanation:

7 0

3 years ago

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