How can air pollution affect plants?

Chemistry

1 answer:

GarryVolchara [31]3 years ago

8 0

Answer:

C. air pollution absorbs carbon dioxide

Explanation:

Carbon dioxide's role in the greenhouse effect is a major contributor to air pollution. Radiation and heat emanating from the earth's surface need to be released out into the atmosphere. But because carbon dioxide levels are so high, there is an ozone effect on the ground level.

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There are 3 main process in the water cycle; evaporation, condensation, and precipitation. What energy source starts the process

Black_prince [1.1K]

Answer:

Sun

Explanation:

Every day, many amounts of water evaporate from lakes and rivers, by heat energy from the sun.

8 0

3 years ago

For each of the following systems at equilibrium, predict whether the reaction will shift to the right, left, or not be affected

bulgar [2K]

Answer:

A - right shift

B - no shift

C - right shift

Explanation:

According to Le Chatelier's principle, when a reaction is in equilibrium and one of the factors affecting the rate of reaction is introduced, the equilibrium will shift so as to annul the effects of the constraint.

In this case, decreasing the volume of the reaction's container is equivalent to increasing the pressure of the reaction. When pressure is increased, the reaction will shift towards the side with a lower number of moles.

In A, the total number of moles on the left-hand side of the reaction is two while it is one on the right-hand side. An increase in pressure will, therefore, see the equilibrium shifting to the right-hand side.

In B, the total number of moles on both the right and the left-hand side is two each. An increase in the pressure will have no effect on the equilibrium.

In C, the total number of moles on the left-hand side is two while it is one on the right-hand side. Hence, an increase in the pressure of the reaction will cause a shift in the equilibrium to the right.

3 0

4 years ago

At a certain temperature, the K p for the decomposition of H 2 S is 0.859 . H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g ) Initially, o

serious [3.7K]

Answer:

P = 0.444 atm

Explanation:

The reaction of decomposition of H₂S is:

H₂S(g) ⇄ H₂(g) + S(g)

Initial 0.245 0 0

Equilibrium 0.245-x x x

The equilibrium constant (Kp) of the above reaction is the following: