HCOOH + H2O <---> HCOO- + H3O+
<span>Ka = 1.8 X 10^-4 = [HCOO-][H3O+] / [HCOOH] </span>
<span>In the solution, [HCOO-] = [H3O+] = x </span>
<span>Quite properly, [HCOOH] = (2.30 X 10^-3 - x). </span>
<span>Since the formic acid solution is pretty dilute, and since Ka is sort of small, we can initially assume that x will be small compared to 2.3 X 10^-3, and so we can ignore it. If we do that, then, </span>
<span>Ka = x^2 / 2.30X10^-3 = 1.80 X 10^-4 </span>
<span>x = 6.4 X 10^-4 = [H3O+] </span>
<span>pH = 3.19 </span>
<span>Now, quite properly, our assumption that x would be small compared to 2.3 X 10^-3 is incorrect, and we really cannot ignore x in that expression. So, we should go back to the original expression for Ka: </span>
<span>Ka = x^2 / (2.30 X 10^-3 - x) = 1.80 X 10^-4 </span>
<span>Quite properly, you should rearrange this into a quadratic form and use the quadratic equation to solve for x. Once you've done that, x = [H3O+], and pH = - log (x).</span>
The correct name of the hydrate iron (ii) sulfite is iron(ii)sulfite heptahydrate
it is gotten as below
find the % composition of FeSO4 = 100-44.26 =55.74 %
find the mole of FeSO4 and H20
= % composition/molar mass
FeSo4 =55.74/151.9 = 0.367 moles
H2O = 44.26/18 =2.459 moles
find the mole ratio by diving each mole with smallest mole
FeSO4 = 0.367/0.367 = 1
H2O = 2.459/0.367 = 7
therefore the name is iron (ii) sulfite heptahydrate is it has seven water molecules
Answer:
metallic bonding
Explanation:
Metallic bonding is bonding where electrons exist as "sea of electrons" meaning they can go anywhere in the structure and are not localized in specific place like covalent bonds are sometimes.
Answer:
C.AgNO3 + NaCl → AgCl + NaNO3
Explanation:
