1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mkey [24]
2 years ago
6

Help please really need help

Chemistry
1 answer:
zheka24 [161]2 years ago
5 0

Answer:

2.14 × 10⁻³ molecules/RSP

3.31 × 10⁻³ molecules/ESP

Explanation:

Step 1: Calculate the number of moles of Acetaminophen per Regular Strength Pill (RSP)

A Regular Strength Pill has 1.29 × 10²¹ molecules of Acetaminophen per pill. To convert molecules to moles we will use Avogadro's number: there are 6.02 × 10²³ molecules in  1 mole of molecules.

1.29 × 10²¹ molecules/RSP × 1 mol/6.02 × 10²³ molecules = 2.14 × 10⁻³ molecules/RSP

Step 2: Calculate the number of moles of Acetaminophen per Extra Strength Pill (ESP)

An Extra Strength Pill has 1.99 × 10²¹ molecules of Acetaminophen per pill. To convert molecules to moles we will use Avogadro's number: there are 6.02 × 10²³ molecules in  1 mole of molecules.

1.99 × 10²¹ molecules/ESP × 1 mol/6.02 × 10²³ molecules = 3.31 × 10⁻³ molecules/ESP

You might be interested in
What happens when an electron moves to a higher energy level? (4.1.4 Quantization)
ale4655 [162]

Answer:

it gains energy in a quantized amount

Explanation:

when we describe the energy of a particle as a quantized ,we mean that only certain values of energy are allowed....it can only gain the exact amount of energy needed to reach one of the higher energy levels

hope this helps :)

4 0
3 years ago
A hypothetical wave has 4.6 J of energy. What is its hypothetical, approximate frequency?
Mariulka [41]

Answer:

6.94 × 10^33Hz

Explanation:

E = hf

Where;

E = Energy of wave (J)

h = Planck's constant (6.626 × 10^-34J/s)

f = frequency (Hz)

According to the information provided in this question, the hypothetical energy of the wave is 4.6J

Hence, using E = hf

4.6 = 6.626 × 10^-34 × f

f = 4.6 / 6.626 × 10^-34

f = 0.694 × 10^34

f = 6.94 × 10^33Hz

3 0
3 years ago
If a weak acid is 25% deprotonated at ph 4, what is the pka?if a weak acid is 25% deprotonated at ph 4, what is the pka?
Oksanka [162]
4.48
pH=pKa+log([A-/HA])

25% deprotonated tells us that A- is .25 and that the rest (75% is protonated) thats .75.

4 = pKa + log\frac{.25}{.75}
4 - log\frac{.25}{.75} = pKa
4.48=pKa

7 0
3 years ago
Read 2 more answers
How many moles are equal to 3.5 grams of beryllium
tamaranim1 [39]

Answer:

w

Explanation:

7 0
3 years ago
Gold atoms can be identified based on the number of which subatomic particles?
sp2606 [1]

Answer: A

Explanation:

A Gold (Au) atom has 79 protons and 79 electrons. A typical gold atom has 118 neutrons, though there are 18 other radioisotopes discovered so far. 79 is its charge (atomic number), which is both its proton number and electron number

7 0
3 years ago
Read 2 more answers
Other questions:
  • 26.2 g piece of copper metal is heated from 21.5°C to 201.6°C. Calculate the amount of heat absorbed by the metal. The specific
    15·1 answer
  • Which diagram represents a physical change,only?
    11·1 answer
  • What are the 4 physical changes you can observe?
    6·2 answers
  • 18.From the following list of aqueous solutions and water, select the one with the highest boiling point.a.1.0 mKNO3b.2.0 mC12H2
    5·1 answer
  • How many moles are in 2.3 grams of phosphorus? :(
    11·1 answer
  • Calculate ΔSrxn∘ for the reaction
    10·2 answers
  • How many moles of HNO3 are present in 697 grams of HNO3?
    13·1 answer
  • You have separate solutions of hcl and h2so4 with the same concentrations in terms of molarity. you wish to neutralize a solutio
    9·2 answers
  • What will be the final temperature when a 25.0 g block of aluminum (initially at 25 °C) absorbs 10.0 kJ of heat? The specific he
    5·1 answer
  • Which of these is a covalent compound?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!