All categories

2 years ago

Only do the ones i have not done brainlest

Mathematics

2 answers:

Leno4ka [110]2 years ago

8 0

Answer:

I don't understand thia

Paul [167]2 years ago

3 0

Answer: 2. y = x times 2.5, 3. y = x - 10, 4. y = x times 6

Step-by-step explanation: I hope that this helps :)

You might be interested in

Least common denominator?

Over [174]

Answer:

$\large\boxed{(s-2)(s+2)(s-3)=(s^2-4)(s-3)=s^3-3s^2-4s+12}$

Step-by-step explanation:

$s^2-4=s^2-2^2=(s-2)(s+2)\\\\\text{used}\ a^2-b^2=(a-b)(a+b)\\\\s^2-5s+6=s^2-2s-3s+6=s(s-2)-3(s-2)=(s-2)(s-3)\\\\\text{Therefore}\ LCD(s^2-4,\ s^2-5s+6)=(s-2)(s+2)(s-3)$

4 0

2 years ago

Need help!!!!!!!! HURRYYYY!!!!!!!!!

svetoff [14.1K]

Answer:

the answer is 168

Step-by-step explanation:

you multiply with by length and you get 168.

7 0

3 years ago

Read 2 more answers

(F x G)(x)<br> F(G(x))<br> G[F(x)]<br> F[G(x)]<br> G(F(x))

pentagon [3]

The results of the composite functions are:

$(f \times g)(x) = 6x^2-9x$

$f(g(x)) = 6x - 3$

$g(f(x)) = 6x - 9$

<h3>What are composite functions?</h3>

Composite functions are functions that are obtained by combining two or more functions together

Assume that:

$f(x) = 2x - 3$

$g(x) = 3x$

Then the computation of the composite functions are as follows:

<h3>Function (f * g)(x)</h3>

$(f \times g)(x) = f(x) \times g(x)$

$(f \times g)(x) = (2x-3) \times (3x)$

$(f \times g)(x) = 6x^2-9x$

<h3>Function f(g(x))</h3>

We have: $f(x) = 2x - 3$

This gives

$f(g(x)) = 2g(x) - 3$

So, we have:

$f(g(x)) = 2(3x) - 3$

$f(g(x)) = 6x - 3$

<h3>Function g(f(x))</h3>

We have: $g(x) = 3x$

This gives

$g(f(x)) = 3f(x)$

So, we have:

$g(f(x)) = 3(2x - 3)$

$g(f(x)) = 6x - 9$

Read more about composite functions at:

brainly.com/question/10687170

4 0

1 year ago

How many ounces in 5 gallons?

liraira [26]

The answer is letter c, also just a tip, all i had to do was ask siri :)

3 0

2 years ago

Read 2 more answers

What is the inverse of y = 16x^2 + 1

tankabanditka [31]

X = 16y^2 + 1
x - 1 = 16y^2
(x - 1)/16 = y^ 2
( (x-1) / 16 ) ^1/2 = y
( (x-1) ^ 1/2 ) / 4 = y

4 0

3 years ago