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olya-2409 [2.1K]
3 years ago
9

Which expressions are equivalent to -9

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer:

<h2><em><u>F </u></em>:   <u>–6x – 9</u>   <em>and</em>   <u><em>B </em></u>:   <u>-9( 2/3x ) - 9(1)</u></h2>

Step-by-step explanation:

if you are on a school computer and dont have access to the image.. pls trust me is F and B for Expanding Expressions Assignment in edge... pls give brainlest :3

skelet666 [1.2K]3 years ago
7 0

Answer:

I think this  right  but I   got it right on  edge

Step-by-step explanation:

Hope   fsdjgsdthisthis this psshelps

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- 65 POINTS -
eduard

Answer: f(x) = ∛(x+4)^2=8 + 3 = 11

4x5=20-9=11

Step-by-step explanation:

3 0
3 years ago
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I am doing this math problem but I do not get it at all this I it Sam and Jesse can wash 5 cars each hour.They work for 7 hours
andreyandreev [35.5K]

They work for 7 hours each day over 2 days, Sam and Jesse washed 2 cars.

5 0
3 years ago
Read 2 more answers
Which of the following is not an identity?
OLga [1]
D. csc^2 x + sec^2 x = 1


The process for each option is to rewrite the equation, attempting to obtain the identity sin^2 x + cos^2 x = 1. In general convert each function to its equivalent using just sin and cos.


A. cos^2 x csc x - csc x = -sin x
cos^2 x * 1/sin x - 1/sin x = -sin x
(cos^2 x * 1/sin x - 1/sin x) * sin x = -sin x * sin x
cos^2 x * 1 - 1 = -sin^2 x
cos^2 x = -sin^2 x + 1
cos^2 x + sin^2 x = 1
Option A is an identity.


B. sin x(cot x + tan x) = sec x
sin x(cos x/sin x + sin x/cos x) = 1/cos x
cos x + sin^2 x/cos x = 1/cos x
cos^2 x + sin^2 x = 1
Option B is an identity.


C. cos^2 x - sin^2 x = 1- 2sin^2 x
cos^2 x - sin^2 x + 2sin^2 x = 1- 2sin^2 x + 2sin^2 x
cos^2 x + sin^2 x = 1
Option C is an identity.


D. csc^2 x + sec^2 x = 1
1/sin^2 x + 1/cos^2 x = 1
cos^2 x/(cos ^2 x sin^2 x) + sin^2 x/(cos^2 x sin^2 x) = 1
(cos^2 x + sin^2 x)/(cos ^2 x sin^2 x) = 1
1/(cos ^2 x sin^2 x) = 1
1 = cos ^2 x sin^2 x
Option D is NOT an identity.


6 0
4 years ago
Mr. Sammie has now decided to expand his food truck business. Based on the information in the chart below, what Region will be b
Nady [450]

Answer:

SouthEast region

Step-by-step explanation:

#We need to find the truck density per region to be able to determine the most viable region for business:

Density=\frac{mass}{Area}\\\\d_{NW}=\frac{320}{10972}=0.0293\  truck/sq \ mi\\\\d_{NE}=\frac{400}{9485}=0.0422\ truck/ sq \ mi\\\\d_{C}=\frac{480}{11645}=0.0412\ truck/sq \ mi\\\\d_{SW}=\frac{515}{11589}=0.0444 \ truck/sq \ mi\\\\d_{SE}=\frac{250}{9933}=0.0252 \ truck/sq \ mi

SouthEast region has the lowest density of 0.0252 truck/sq mi hence the best region for expansion.

-A low food truck density is an indicator of a relatively low competition hence existance of a large market share yet to be dominated.

6 0
4 years ago
TU=2x, UB=3x+1, TB=21
Stella [2.4K]
X would be equal to 21/8
8 0
3 years ago
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