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WITCHER [35]
3 years ago
5

A website offers a coupon such that each customer has a 15% chance of getting the coupon every day they visit. Aya visits the we

bsite 6 consecutive days. What is the probability that aya will offered a coupon on at least one of the days she visit the website
Mathematics
1 answer:
Advocard [28]3 years ago
5 0
Dkajnsuzhsisnsmeskms
Ms
SMS
S
SMS
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What are the points on y-axis which are at a distance of 4 units from 4x+3y=12
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Given:

The equation of line is

4x+3y=12

To find:

The points on y-axis which are at a distance of 4 units from the given line.

Solution:

The point lie on the y-axis. So, their x-coordinate must be zero.

Let the points are in the form of (0,k).

The distance between a point (x_0,y_0) and a line ax+by+c=0 is

d=\dfrac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}

The given equation can be written as

4x+3y-12=0

The distance between (0,k) and 4x+3y-12=0 is 4 units.

4=\dfrac{|4(0)+3(k)-12|}{\sqrt{4^2+3^2}}

4=\dfrac{|0+3k-12|}{\sqrt{16+9}}

4=\dfrac{|3k-12|}{\sqrt{25}}

4=\dfrac{|3k-12|}{5}

Multiply both sides by 5.

20=|3k-12|

\pm 20=3k-12

12\pm 20=3k

\dfrac{12\pm 20}{3}=k

Now,

k=\dfrac{12-20}{3}\text{ and }k=\dfrac{12+20}{3}

k=\dfrac{-8}{3}\text{ and }k=\dfrac{32}{3}

Therefore, the two points are \left(0,\dfrac{-8}{3}\right)\text{ and }\left(0,\dfrac{32}{3}\right).

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