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expeople1 [14]
4 years ago
5

Look back at your data and your regression equation. (Sample data is shown to the right, with x = pressure and y = volume.) Chec

k all statements that are true.
As the pressure of the gas increased, the volume of the gas decreased.

For all pairs of data of pressure and volume, P • V was appoximately the same.

For all pairs of data of pressure and volume, P • V mr001-1.jpg k for the same value k.

The regression equation was of the form V = kP–1 (which is the same as V = k/P).

Chemistry
2 answers:
Eduardwww [97]4 years ago
8 0

Answer:

All of the answers are true, or A, B, C, D.

Explanation:

VARVARA [1.3K]4 years ago
3 0
The answer is: all true

<span>A. As the pressure of the gas increased, the volume of the gas decreased.
It is clear that if you compare the data on the left side. When the pressure increased the volume is decreased.

B. For all pairs of data of pressure and volume, P • V was appoximately the same.
The pressure is inversely related to the volume. You can take two data to prove it. Let use the first and second data
V * P= 1.03 * 50= 51.5
</span>V * P= <span>1.08 * 47.5= 51.3

C. For all pairs of data of pressure and volume, P • V mr001-1.jpg k for the same value k.
D. The regression equation was of the form V = kP–1 (which is the same as V = k/P).
The value of k can be expressed as k= P*V. If the equation is turned around, it could be expressed as V= k/P
The value of k is constant on different data, proved by the calculation on the second statement above. The value of k should be around 51.5
</span>
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What did Aristotle believe?
34kurt

Answer:

He believed in biology

Explanation:

he believed the world was made up of individuals.

8 0
4 years ago
Rearrange the equation for the area of a rectangle (A=l x w) to solve for length, L
Mariana [72]
Not sure if this is what you mean but l= A/w
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4 years ago
1.00 mole of an ideal gas at STP is cooled to -41°C while the
qwelly [4]

Answer:

V₂ = 18.13 L

Explanation:

Given data:

Mole of gas = 1 mol

Initial temperature = 273 K

Initial pressure = 1 atm

Final volume = ?

Final temperature = -41°C (-41+273 = 232 K)

Final pressure = 805 mmHg (805/760 = 1.05 atm)

Solution:

First of all we will calculate the initial volume of gas.

PV = nRT

V = nRT/P

V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm

V = 22.4 L/atm / 1 atm

V = 22.4 L     ( initial volume)

Now we will determine the final volume by using equation,

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 22.4 L ×  232 K / 273 K × 1.05 atm

V₂ = 5196.8 atm .L. K / 286.65 atm.K

V₂ = 18.13 L

5 0
3 years ago
Every day, about 1 4 0 , 0 0 0 , 0 0 0 140,000,000140, comma, 000, comma, 000 plastic water bottles are bought in the United Sta
jeka94

Answer:

0.875 time.

Explanation:

The length of plastic water bottles are bought in the United States every day = (the no. of plastic water bottles are bought every day)(length of each bottle) = (140.0 million bottle)(0.25 m) = 35.0 million meter.

The length of the equator of the earth = 40.0 million meter.

∴ The times can the Earth's equator be circled by a line of plastic bottles used in the United States every day = (The length of plastic water bottles are bought in the United States every day)/(The length of the equator of the earth) = (35.0 million meter)/(40.0 million meter) = 0.875 times.

8 0
4 years ago
Vegetable oil has a specific heat of 1.67/* Calculate the heat required (in kilojoules) to raise the temperature of 500 g of
Nady [450]

Answer:

Q=108.55kJ

Explanation:

Hello,

In this case, we can compute the required heat by using the following equation:

Q=mCp(T_2-T_1)

Thus, by considering the given mass, specific heat and both initial and final temperature, we obtain:

Q=500g*1.67\frac{J}{g\°C} *(150.0\°C-20.0\°C)*\frac{1kJ}{1000J} \\\\Q=108.55kJ

Regards.

5 0
3 years ago
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