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7nadin3 [17]
4 years ago
9

50 points!!! Match the definition to the keyword.

Chemistry
2 answers:
insens350 [35]4 years ago
4 0

Answer:

This is the same order as the definitions

1.

5.

3.

2.

4.

 Hope it helps

krok68 [10]4 years ago
3 0

Answer:

Cristae = 1

Diffusion = 4

Semipermeable = 3

Fermentation = 5

Carbon Fixation = 2

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Calcium carbide reacts with water to produce acetylene gas according to the following equation: CaC2(s) + 2H2O(l)C2H2(g) + Ca(OH
poizon [28]

Answer:

33.7

Explanation:

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7 0
3 years ago
If electromagnetic radiation has a frequency of 2.0×1015s−1, what is the radiation’s energy?(1 point)
Alika [10]
  • Frequency=v=2×10^15Hz
  • Energy=E

Using planks quantum theory

\\ \sf\longmapsto E=hv

\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 2\times 10^{15}s^{-1}

\\ \sf\longmapsto E=13.252\times 10^{-19}J

\\ \sf\longmapsto E=1.3\times 10^{-18}J

7 0
3 years ago
How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *
densk [106]

Answer:

26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃

Explanation:

To determine the number of moles of O₂ that are needed to react completely with 35.0 mol of FeCl₃, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction),  and rule of three as follows: if 4 moles of FeCl₃ react with 3 moles of O₂, 35 moles of FeCl₃ with how many moles of O₂ will it react?

molesofO_{2} =\frac{35 moles of FeCl_{3}*3 moles of O_{2}  }{4 moles of FeCl_{3}}

moles of O₂= 26.25 ≅ 26.3

<u><em>26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃</em></u>

7 0
3 years ago
12. help idk what to do at this point , I have notes and study till 3am , I still need help
GaryK [48]
I’m not good at this but I’m guessing it’ll be the first one!
5 0
3 years ago
Read 2 more answers
Plz plz plz plz answer I have not much time<br> Fourth option is a neutral boron atom.
jarptica [38.1K]
A is correct hope this helps
4 0
3 years ago
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