Let X be the first number
there is a 2 numbers distance between each even number eg.2 ,4, 6, 8, etc.
So the 2nd number is X+2
The sum of the 1st and 2nd numbers = 14
X + X+2 =14
2X +2 =14
2X = 14-2
2X = 12
X = 12/2
X = 6
Therefore,
The first number i.e, X = 6
And the second number i.e, X+2 = 6+2 =8
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This is the only positive pair in case of two consecutive numbers if the are even numbers but not consecutive there will be more pairs
12 + 2 = 14
10 + 4 = 14
8 + 6 = 14 (Already found)
x=0 or x=4
just factorize basically
cancels the x’s so it’d be 3x-12=0 and from that x=4
Answer:
Not Determinable
Step-by-step explanation:
Simplifying
Ln(4x + 1) = 6
Reorder the terms:
nL(1 + 4x) = 6
(1 * nL + 4x * nL) = 6
(1nL + 4nxL) = 6
Solving
1nL + 4nxL = 6
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Reorder the terms:
-6 + 1nL + 4nxL = 6 + -6
Combine like terms: 6 + -6 = 0
-6 + 1nL + 4nxL = 0
The solution to this equation could not be determined.
Answer:
x=136°
Step-by-step explanation:
x=180°-(180-(46+90))
x=180-44
x=136
