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frozen [14]
2 years ago
5

1 1

Mathematics
1 answer:
andrey2020 [161]2 years ago
6 0

Answer:

the answer should be 3/10

Step-by-step explanation:

if you look at the photo you can solve it from there

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Use the IVT to prove that one solution to <img src="https://tex.z-dn.net/?f=x%5E%7B3%7D%20%2Bx-5%3D0" id="TexFormula1" title="x^
Dafna11 [192]

Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since

<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0

and

<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0

it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.

7 0
3 years ago
Consider quadrilateral BCEF inscribed in circle A. Diagonals EB and CF intersect at point D. Select all the statements that are
Elena L [17]

Answer:

m\angle ECB+m\angle EFB=180

m\angle CDB\cong m\angle EDF

m\angle CDB+m\angle DCB+m\angle CBD=180 \degree

Step-by-step explanation:

From the diagram, quadrilateral BCEF is a cyclic quadrilateral.

Opposite angles if a cyclic quadrilateral sum up to 180°

m\angle ECB+m\angle EFB=180

The diagonals intersect at D to form two pairs of vertical angles, and vertical angles are congruent.

m\angle CDB\cong m\angle EDF

Also sum of angles in triangle CBD is 180°.

m\angle CDB+m\angle DCB+m\angle CBD=180 \degree

6 0
2 years ago
PLEASE HELP I GIVE THANKS
VashaNatasha [74]
It is an obtuse triangle because all of the sides are diffrent amount

5 0
3 years ago
Read 2 more answers
Billy was counting the number of wheels and bike seats at the playground. He saw tricycles and bicycles. He counted 79 wheels an
mart [117]
I think the answer is 25.5. Although, I don't know how you would have half a bike unless there was a 3 wheel bike which would make the answer 24.
7 0
3 years ago
What is hs the answer to this question?<br><br> Y= 5x+5<br> Y - x=5
ANEK [815]
Y = 5x + 5
y - x = 5

You can use substitution to solve this system. Use y's expression (5x + 5) for y in the second equation to solve for x:

y - x = 5
5x + 5 + x = 5
6x + 5 = 5
6x = 0
x = 0

Substitute your value for x into one of the original equations to y:

y = 5x + 5
y = 5(0) + 5
y = 5

Finally, substitute both values into both original equations to check your work:

5 = 5(0) + 5    -->    5 = 5    <--True
5 - 0 = 5    -->    5 = 5    <--True

Answer:
x = 0
y = 5
3 0
3 years ago
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