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d1i1m1o1n [39]
3 years ago
10

Demonstrate how you can derive our 9.8m/s^2 from Newton's general law of gravity.

Physics
1 answer:
AlexFokin [52]3 years ago
3 0

Answer:

g=G\frac{m_E}{r^2}

Explanation:

Using Newton's Law of Universal Gravitation, we can write:

F=G\frac{m_E}{r^2}, where G is gravitational constant 6.67\cdot 10^{-11}, m_E is Earth's mass, and r is Earth's radius.

Using these measured values, we have:

F=6.67\cdot 10^{-11}\frac{5.97\cdot 10^{24}}{(6.38\cdot10^6)^2},\\g\approx \fbox{$9.8\:\mathrm{m/s^2}$}.

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<h3>→ D. has no overall force acting on it.</h3>
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A train travels 4200 km in 90 hours. What is its speed?
denis23 [38]

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professor190 [17]

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