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slamgirl [31]
3 years ago
8

Cody’s car accelerates from 0m/s to 45 m/s northward in 15 seconds. What is the acceleration of the car?

Physics
1 answer:
Tems11 [23]3 years ago
6 0

Explanation:

v=v(initial)+at

45=0+15a

a= 3m/sec²

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Por favor, necesito ayuda urgente 4. vectores perpendiculares de 25 y 40 unidades cada uno. Hallar gráfica y numericamente el ve
Darina [25.2K]

Answer:

4)  R = 47.17 units , 5)  R= 10,29 unidades, 6)   R= 2994,4 km ,    θ = -33,7

Explanation:

Este es un ejercicio de adición de vectores

4) como los vectores son perpendiculares.

Para encontrar la resultante podemos usar el teorema de pitoras

        R =  √ a² + b²

        R = √√ ( 25² + 40²)

        R =  47,17 unidades

5)  Este caso como el angulo es diferente de 90 debemos usar la relación de pitoras completa

        R² =  a² + b² + 2 a b cos θ

donde el angulo es entre los vectores a y b

        R² = 12² + 16² – 2 12 16 cos 40

        R²= 400 – 294,16

       R= 10,29 unidades

6) En este caso los dos desplazamientos son perpendiculares, por lo cual Usamos el teorema de Pitágoras

          R = √ (2400² + 1600²)

          R= 2994,4 km

para el angulo de este desplazamiento usamos trigonometría

           tan θ = y/x

           θ = tan⁻¹ y/x

           θ = tan⁻¹ 1600/(-2400)

           θ = -33,7  

TRASLATE

This is a vector addition exercise

4) as the vectors are perpendicular.

To find the result we can use the Poreor theorem

        R = √ a² + b²

        R = √ (25² + 40²)

        R = 47.17 units

5) This case, as the angle is different from 90, we must use the complete ratio of the pitoras

        R² = a² + b² + 2 a b cos θ

where the angle is between vectors a and b

        R² = 12² + 16² - 2 12 16 cos 40

         R² = 400 - 294.16

       R = 10.29 units

6) In this case the two displacements are perpendicular, which is why we use the Pythagorean theorem

          R = √ (2400² + 1600²)

          R = 2,994.4 km

for the angle of this displacement we use trigonometry

           tan θ = y / x

           θ = tan⁻¹ y / x

           θ = tan⁻¹ 1600 / (- 2400)

           θ = -33.7

3 0
3 years ago
It is weigh-in time for the local under 85 kg rugby team. The bathroom scale used to assess eligibilty can be described by Hooke
Varvara68 [4.7K]
<span>k = 1.7 x 10^5 kg/s^2 Player mass = 69 kg Hooke's law states F = kX where F = Force k = spring constant X = deflection So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration. F = kX F/X = k 115 kg* 9.8 m/s^2 / 0.65 cm = 115 kg* 9.8 m/s^2 / 0.0065 m = 1127 kg*m/s^2 / 0.0065 m = 173384.6154 kg/s^2 Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2 Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So X/0.39 cm = 115 kg/0.65 cm X = 44.85 kg/0.65 X = 69 kg The player masses 69 kg.</span>
4 0
3 years ago
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We beat a blanket with a stick to remove dust particles why​
lutik1710 [3]

Answer:

removing the dust particles cleans the blanket

6 0
3 years ago
The acceleration of an object (in m/s2) is given by the function a ( t ) = 6 sin ( t ) a(t)=6sin(t). The initial velocity of the
levacccp [35]

Answer:

v(t)=-6cos(t)+4

Explanation:

We have acceleration given by

a(t)=6sin(t)

Velocity at t = 0

v(0)=-2\ m/s

Velocity is given by

v(t)=\int a(t)dt\\\Rightarrow v(t)=\int 6sin(t)dt\\\Rightarrow v(t)=6\int sin(t)\\\Rightarrow v(t)=-6cost+C

at t = 0

-2=-6cos0+C\\\Rightarrow -2+6=C\\\Rightarrow C=4

The equation will be

\mathbf{v(t)=-6cos(t)+4}

8 0
3 years ago
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How long does it take an airplane to fly 5000m if it maintains a speed of 240 meters per second
Rudiy27

Answer:

20.83

Explanation:

5000/240

7 0
3 years ago
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