Ask question

Ask question

All categories

schepotkina [342]

2 years ago

5

What is the speed of an 800 kg automobile if it has a kinetic energy of 9.00 x 10^J?

1 answer:

MA_775_DIABLO [31]2 years ago

7 0

Ek = 1/2 mv^2

9 × 10^4 = 1/2 × 800 × v^2

9 × 10^4/400 = 400 v^2 / 400

9 × 10^4/400 = v^2

√225 = v

15 ms⁻¹ = v

That's the only way I know how to work it out

I think in this case velocity and speed would be considered the same because me

s = d/t and v=d/t

one is distance travelled and the other is displacement of a body

You might be interested in

What Is the volume of the rectangular prism of 6cm 9cm and 5cm

Crazy boy [7]

Volume is length times width times height, so 6 times 9 times 5 is 270 centimeters.

8 0

3 years ago

What is lower body strength

Lerok [7]

Lower body strength is the ability of the body to exert a maximum force against an object external to the body in one maximum effort of the lower body muscles. Gluteals are muscles that make up the buttocks. ... Their roles are to facilitate hip extension and lift the leg to the side.

3 0

2 years ago

Read 2 more answers

What is the medium the energy in the slinky wave travels through?

vlabodo [156]

Answer:

The metal coil of the slinky

Explanation:

The wave travels on the actual slinky which we see deforming as the wave goes through.

6 0

3 years ago

Read 2 more answers

If the volume is held constant, what happens to the pressure of a gas as temperature is decreased? Explain.

Lady bird [3.3K]

Answer:Decreases

Explanation:

Given

Volume is held constant that is it is a isochoric process.

We know that

PV=nRT

as n,V& R are constant therefore only variables are

P & T

so $\frac{P_1}{T_1}=\frac{P_2}{T_2}$

$\frac{P_1}{P_2}=\frac{T_1}{T_2}$

As $T_1$ is decreasing therefore Pressure must also decrease so that ratio remains constant.

6 0

3 years ago

You obtain a 100-W light bulb and a 50-W light bulb. Instead of connecting them in the normal way, you devise a circuit that pla

lesantik [10]

Answer:

When they are connected in series

The 50 W bulb glow more than the 100 W bulb

Explanation:

From the question we are told that

The power rating of the first bulb is $P_1 = 100 \ W$

The power rating of the second bulb is $P_2 = 50 \ W$

Generally the power rating of the first bulb is mathematically represented as

$P_1 = V^2 R$

Where $V$ is the normal household voltage which is constant for both bulbs

So

$R_1 = \frac{V^2}{P_1 }$

substituting values

$R_1 = \frac{V^2}{100}$

Thus the resistance of the second bulb would be evaluated as

$R_2 = \frac{V^2}{50}$

From the above calculation we see that

$R_2 > R_1$

This power rating of the first bulb can also be represented mathematically as

$P_ 1 = I^2_1 R_1$

This power rating of the first bulb can also be represented mathematically as

$P_ 2 = I^2_2 R_2$

Now given that they are connected in series which implies that the same current flow through them so

$I_1^2 = I_2^2$

This means that

$P \ \alpha \ R$

So when they are connected in series

$P_2 > P_1$

This means that the 50 W bulb glows more than the 100 \ W bulb

3 0

3 years ago