For function one, the slope is already in mx+b form. The coefficient to x is the slope, so it is four in this case. For the second function we calculate the slope using rise over run. The rise is change in y and run is change in x, so 4/2= 2 slope. Four is greater than two so it has the greater rate of change. The answer is B
Answer:
whts the question??
Step-by-step explanation:
Answer:
Ix = Iy =
Radius of gyration x = y =
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is . Moment of inertia of quarter disk about its perpendicular is .
Now using perpendicular axis theorem, Ix = Iy = = .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
D. passive
Step-by-step explanation:
No, it is not a function.
Since all the lines have been drawn in the grid line do not have any connection between them even a point in common.
I hope this has been useful for you.