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3 years ago

MHA FANS FINISH THE MEME who's that Pokémon? Fudge! -bakugou

1 answer:

4 0

keep it gouing enveer stop the ifght fro Gotta catch em all just gotta ond you dad ash he left cux ur mom nvever loved him go go pokemon oh yeah go go pokemon supersayn pikachu time to go ultra INSTIFNCNCNCNCNT ya bakugo loves to play with fire and zuko is the sole of the entire show ya ya go go unlce iroh give some of that opium teaaaaaaaaaaa

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A compound containing phosphorus and oxygen has a molar mass of 219.9 g/mol and an empirical formula of p2o3. Determine its mole

Softa [21]

Answer:

P₄O₆

Explanation:

The molecular formula is a whole number multiple of the empirical formula. that is, if the mole wt is 219.9 gms/mole and the empirical formula weight is 110 gms/mole*, then the whole number multiple is 219.9/110 = 2 => Molecular formula => (P₂O₄)₂ => P₄O₆.

7 0

3 years ago

Which statement about subatomic particles is true?

Lera25 [3.4K]

Answer:

Explanation:

6 0

3 years ago

Why might Marie Curie have been motivated to teach the children of beet workers?

pav-90 [236]

Marie curie worked as a governess and she was awarded noble prize for her discoveries.

Explanation:

When Marie curie worked as a governess for three years her employer allowed her to teach reading to the children of peasant workers at his beet sugar factory. This was banned under Russian rule. During that time she studied chemistry lessons from her father by mail.

Marie curie was awarded the Noble prize in chemistry for her discoveries and studies of elements radium and polonium. She is the only women who is awarded the Noble prize twice.

She made her first research into the treatment of tumors with radiation and founded a Curie institutes, that are important medical research centers.

6 0

3 years ago

To begin the experiment, 1.11g of methane CH4is burned in a bomb calorimeter containing 1000 grams of water. The initial tempera

navik [9.2K]

1. CH4 + 2O2 → CO2 + 2H2O
2. 10.80 degrees celsius
3. 45,187 J
4. 7,506 J
<span>5. 52,693 J </span>

6 0

3 years ago

Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe

Illusion [34]

Answer:

a. Kp=1.4

$P_{A}=0.2215 atm$

$P_{B}=0.556 atm$

b.Kp=2.0 * 10^-4

$P_{A}=0.495atm$

$P_{B}=0.00995 atm$

c.Kp=2.0 * 10^5

$P_{A}=5*10^{-6}atm$

$P_{B}=0.9999 atm$

Explanation:

For the reaction

A(g)⇌2B(g)

Kp is defined as:

$Kp=\frac{(P_{B})^{2}}{P_{A}}$

The conditions in the system are:

A B

initial 0 1 atm

equilibrium x 1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.

Replacing these values in the expression for Kp we get:

$Kp=\frac{(1-2x)^{2}}{x}$